Question

How many solutions exist for the given equation?

Answer 1

Answer:

One solution $x=2$

Step-by-step explanation:

Given the equation

$0.5(x+12)=4x-1$

First, multiply this equation by 10:

$10\cdot 0.5(x+12)=10(4x-1)\\ \\5(x+12)=40x-10\\ \\5x+60=40x-10$

Separate terms with x and without x in different parts of the equation:

$5x-40x=-10-60\\ \\-35x=-70\\ \\35x=70\\ \\x=\dfrac{70}{35}\\ \\x=2$