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Shalnov [3]
3 years ago
9

Lara has noticed that all of her friends are very careful about what they eat, and they are all much thinner than she is. She wa

nts to be healthy, but she really wants to fit in with her friends. What is the best step for Lara to take?
A. Talk to a trusted adult to help her evaluate her eating and exercise in a healthy way.
B.Ask her friends how they stay so thin, and use the same strategies.
C. Find new friends who are not as thin so she doesn't feel any pressure.
D.Try out the newest diet she's seen advertised on TV to help her lose the weight she wants to lose.
Physics
2 answers:
nlexa [21]3 years ago
7 0

A. Talk to a trusted adult to help her evaluate her eating and exercise in a healthy way.


HACTEHA [7]3 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

If Lara wants to be healthy, and really wants to fit in with her friends then she should talk to a trusted adult to help her evaluate her eating and exercise in a healthy way.

This is because a trusted person will give her beneficial advice as compared to any other person or any advertisement on TV which may promise false results in order to sell their product.

This may also lead to harmful effects on her health. Thus, she should eat and exercise in a healthy way.

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A -3.00 nc point charge is at the origin, and a second -5.50 nc point charge is on the x-axis at x = 0.800 m. find the electric
Liula [17]

The electric field produced by a single-point charge is given by

E(r)=k\frac{q}{r^2}

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q is the charge

r is the distance from the charge


To find the electric field at x=0.200 m, we need to find the electric field produced by each charge at that point, and then find their resultant.


1) The first charge is q=-3.00 nC=-3.00 \cdot 10^{-9} C, and it is located at x=0, so its distance from the point x=0.200 m is

r=0.200 m-0=0.2 m

Therefore, the electric field is

E_1=(8.99 \cdot 10^9 Nm^2C^{-2})\frac{(3.0 \cdot 10^{-9} C)}{(0.2 m)^2}=675 N/C

And since the charge is negative, the direction of the field is toward the charge, so toward negative x direction.


2) The second charge is q=-5.50 nC=-5.5 \cdot 10^{-9}C and it is located at x=0.800 m, so its distance from the point is

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Therefore, the electric field is

E_2 = (8.99 \cdot 10^9 Nm^2C^{-2})\frac{(5.5 \cdot 10^{-9} C)}{(0.6 m)^2}=137.5 N

And since the charge is negative, the direction of the field is toward the charge, so toward positive x-direction.


3) The total electric field at x=0.200 m will be given by the difference between the two fields (because they are in opposite directions). Taking the x-positive direction as positive direction, we have

E=E_2 -E_1 =137.5 N/C/C-675 N/C=-537.5 N/C

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3 years ago
THE PROBLEM!
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Answer: 15.29

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