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stealth61 [152]
3 years ago
11

How can forgery be used in crime

Chemistry
2 answers:
xxTIMURxx [149]3 years ago
4 0

Forgery is basically the imitation of documents, contracts, Identification cards, or any legal certificate.  

Imitated documents, contracts, ID cards etc can be used in any crime. And in many states forgery is said to be a fraud.  

Anything can be forged and used in somewhere as an original document, certificate, ID card etc, which is indeed a crime.  

Some common examples are imitating legal documents to have someone’s property or business, using of imitated certificates to get jobs in companies, forgery signature on someone’s checks to take out cash, etc.  

These all are crimes.

Tems11 [23]3 years ago
3 0

Some bad people will tend to forge dollar bills and make fake bills, giving them to cashiers and asking for it to be split into a different amount of bills so they are given real cash and wont be caught or they will buy things, return them and be given back real money and get away with it. This is obviously a crime because it's fake.

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The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})  (in terms of mass)

or, q=\Delta H_{fusion}\times Moles     (in terms of moles)

Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

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