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nikitadnepr [17]
3 years ago
11

4. Jake surveyed his 25 classmates on their favorite flavor of

Chemistry
1 answer:
Eddi Din [679]3 years ago
4 0

Answer:

J

Explanation:

In total there are 25 students. If you add up all the other students who liked flavors other than strawberry twist you will get 14. That means 14/25 students did not favor strawberry twist, while the other 11/25 did.

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Science plz help due soon 6th grade Major grade
pentagon [3]

Answer:

the answer is d.

Explanation:

because the core is deepest then is the mantle and the lithpsphere is last .

I put a picture incase you need a visual example.

5 0
3 years ago
A 25.00 ml sample of hydrochloric acid solution, hcl, is titrated with 0.0512 m naoh solution. the volume of naoh solution requi
Tresset [83]

A 25.00 ml sample of hydrochloric acid solution, HCl, is titrated with 0.0512 m NaOH solution. the volume of NaOH solution required is 21.68 ml  then the molarity of the HCl solution is 0.044 M .

Calculation ,

Formula used : M_{1} V_{1} =M_{2} V_{2}                            ...( i )

Where M is the molarity or concentration and V is the volume in ml .

concentration of hydrochloric acid solution ( M_{1}    ) = ?

concentration of NaOH ( M_{2} ) = 0.0512 M

volume of hydrochloric acid solution  ( V_{1} ) = 25.00 ml

volume of NaOH ( V_{2} ) =  21.68 ml

Putting the value of concentration , volume of both  in equation ( i ) we get .

M_{1}   × 25.00 ml = 0.0512 × 21.68 ml

M_{1}    = 0.0512 × 21.68 ml / 25.00 ml= 0.044 M

to learn more about hydrochloric acid solution please click here ,

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5 0
1 year ago
The bond that forms between two nonmetal elements will be
Troyanec [42]
It is a covalent bond
8 0
3 years ago
Sr 32.8 g, Si 5.2 g and O 11.9 g empirical formula number 11
horsena [70]

\boxed{\begin{array}{c|c|c|c|c}\boxed{\sf Element}&\boxed{\sf Mass\:in\: compound}&\boxed{\sf No\:of\:moles}&\boxed{\sf Ratio}&\boxed{\sf Simplified\:ratio}\\ \sf Sr &\sf 32.8g &\sf \dfrac{32.8}{87}=0.37&\sf \dfrac{0.37}{0.18}=2.05&\sf 2 \\ \sf Si &\sf 5.2g &\sf \dfrac{5.2}{28}=0.18 &\sf \dfrac{0.18}{0.18}=1&\sf 1\\ \sf O&\sf 11.9g &\sf \dfrac{11.9}{16}=0.74&\sf\dfrac{0.74}{0.18}=4.1 &\sf 4\end{array}}

Empirical formula:-

\\ \sf\longmapsto SiSr_2O_4

8 0
2 years ago
How many grams of O2(g) are needed to completely burn 55.9 g of C3H8(g)?
dem82 [27]

The balanced chemical reaction will be:

C3H8 + 5O2 = 3CO2 +4H2O

We are given the amount of propane gas to be burned. This will be our starting point.

 55.9 g C3H8 ( 1 mol C3H8 / 44.1 g C3H8 ) ( 5 mol O2/1 mol C3H8)(32 g O2 / 1 mol O2) = 202.81 g O2

3 0
3 years ago
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