Answer: 1.00 M
Explanation:
Moles of Solute/Liters of Solution = molarity. Then you would do 0.500 Moles/ 0.500 L and you get 1.00 M.
The mass of 1.72 mol of magnesium fluoride is 107 grams.
To determine the mass of 1.72 mol of magnesium fluoride, we first need the chemical formula of magnesium fluoride. Magnesium forms a +2 ion (Mg+2) and fluoride forms a -1 ion (F-1). Since all compounds formed from ions have to be electrically neutral, we need 2 fluoride ions and 1 magnesium ion. Therefore, the formula for magnesium fluoride is MgF2.
Now we need to determine the molar mass of the compound from the molar mass values from the periodic table. Let's use a table to calculate this molar mass.
Molar mass of MgF2
Element Molar Mass (g/mol) Quantity Total (g/mol)
Mg 24.31 1 24.31
F 19.00 2 38.00
Total molar mass of MgF2 = 24.31 g/mol + 38.00 g/mol = 62.31 g/mol
This is the mass of one mole of the substance. If we have 1.72 mols of it, we multiply 1.72 by 62.31.
1.72 mol (62.31 g/mol) = 107 grams
We rounded to 107 to keep the correct number of significant digits in our answer.
Answer: Option (c) is the correct answer.
Explanation:
In liquids, molecules are held by slightly less strong intermolecular forces of attraction as compared to solids.
Hence, molecules of a liquid are able to slide past each other as they have more kinetic energy than the molecules of a solid.
As a result, liquids are able to occupy the shape of container in which they are placed. Also, liquids have fixed volume but no fixed shape.
Thus, we can conclude that liquids have a variable shape and a fixed volume.
It would have a charge of 4+
