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EleoNora [17]
3 years ago
13

What is the mass of bromine in 11.2g of MgBr2?​

Chemistry
1 answer:
True [87]3 years ago
8 0

Answer:

9.72 grams of Br

Explanation:

This is the salt: MgBr₂ (Magnesium bromide)

1 mol of MgBr₂ has 1 mol of Mg and 2 mol of Br

Molar mass MgBr₂ → 184.11 g/m

So the rule of three will be:

184.11 g of salt have 2 moles of Br

11.2 g of salt have (11.2 . 2)/184.11 = 0.122 moles of Br.

Molar mass Br = 79.9 g/m

Mol . molar mass = mass → 0.122 m . 79.9 g/m = 9.72 g

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Negatively charged Adam or group of Adams is called a(n)
bija089 [108]

Answer:

Anion

Explanation:

Anion is an atom or group of atoms that are negatively charged.

Cations are positively charged

Anode is a positively charged pole that conducts electricity (remember electrolysis)

Cathode is a negatively charged pole that conducts electricity (remember electrolysis too)

3 0
3 years ago
Does anyone have geometry on edg ??!!!
AfilCa [17]
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3 0
2 years ago
What is the total energy change for the following reaction:CO+H2O-CO2+H2
Alekssandra [29.7K]

Answer:

\large \boxed{\text{-41.2 kJ/mol}}

Explanation:

Balanced equation:    CO(g) + H₂O(g) ⟶ CO₂(g) + H₂(g)

We can calculate the enthalpy change of a reaction by using the enthalpies of formation of reactants and products

\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)

(a) Enthalpies of formation of reactants and products

\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{CO(g)} & -110.5 \\\text{H$_{2}$O} & -241.8\\\text{CO$_{2}$(g)} & -393.5 \\\text{H$_{2}$(g)} & 0 \\\end{array}

(b) Total enthalpies of reactants and products

\begin{array}{ccr}\textbf{Substance} & \textbf{Contribution)/(kJ/mol})&\textbf{Sum} \\\text{CO(g)} & -110.5& -110.5 \\\text{H$_{2}$O(g)} &-241.8& -241.8\\\textbf{Total}&\textbf{for reactants} &\mathbf{ -352.3}\\&&\\\text{CO}_{2}(g) & -393.5&-393.5 \\\text{H}_{2} & 0 & 0\\\textbf{Total}&\textbf{for products} & \mathbf{-393.5}\end{array}

(c) Enthalpy of reaction \Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)= \text{-393.5 kJ/mol - (-352.3 kJ/mol}\\= \text{-393.5 kJ/mol + 352.3 kJ/mol} = \textbf{-41.2 kJ/mol}\\ \text{The total enthalpy change is $\large \boxed{\textbf{-41.2 kJ/mol}}$}

4 0
3 years ago
For the following reaction, the equilibrium constant Kc is 0.80 at a certain temperature. If the concentration of NO(g) and NOBr
velikii [3]

Answer:

[Br₂] =  1.25M

Explanation:

        2NO (g)  +  Br₂ (g)   ⇄   2NOBr (g)

Eq    0.80M            ?                0.80M

That's the situation told, in the statement.

Let's make the expression for Kc

Kc = [NOBr]² / [Br₂] . [NO]²

Kc = 0.80² / [Br₂] . [0.80]²

0.80 = 1 / [Br₂]

[Br₂] = 1 / 0.80 → 1.25

4 0
3 years ago
Who is considered the father of atomic theory?
Sati [7]

John Dalton is considered the father of the atomic theory. In 1800s he had came up with 5 concepts regarding the atomic theory.

Hope I helped.

4 0
3 years ago
Read 2 more answers
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