Question

What volume (in L) of H2 would be collected at 22.0oC and a pressure of 713 torr if 2.65 g of zinc react according to the equation:
Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)

Please provide the steps and explanations. I truly do not know where to start with this question.
Thanks

Answer 1

Answer: 83.74L

Explanation:

Temp. = 295K

P = 713torr = 0.938atm

Mass = 2.65g

PV = nRT

V = nRT/PV

n = Mass/Molar mass

Molar mass of Hydrogen gas = 1.00784*2= 2.0156g/mok

n = 2.65/2.0156 = 1.31469mol

V = 1.31469*0.08205*295/0.938

V = 83.74L

The volume = 83.74L