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3 years ago

How is 10 /2 Equal to 1/5

Mathematics

1 answer:

uysha [10]3 years ago

6 0

Answer:

Its not

Step-by-step explanation:

If you mean how is 2/10 equal to 1/5, then it is because 2 divided by 10 gives you the same answer (0.2) that 1 divided by 5 does.

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An analysis of the decay of 10 grams of an unstable element over time was completed and is displayed in the computer output.

Lady bird [3.3K]

The equation of the least-squared regression line is: In(Element) = 2.305 - 0.101(Time).

<h3>What is a regression line?</h3>

A regression line displays the connection between scattered data points in any set. It shows the relation between the dependent y variable and independent x variables when there is a linear pattern.

According to the given problem,

From the table we can see,

ln(Element) is the dependent variable and Time is the independent variable.

The constant = 2.305,

Time = -0.101

Hence, we can conclude, our least squared regression line will be

In (Element) = 2.305 - 0.101 (Time).

Learn more about regression line here: brainly.com/question/7656407

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6 0

2 years ago

Which example models a negative integer A.Students in a classroom B. The age of a parent C. Money lost from a pocket D. the heig

Rufina [12.5K]

Answer:

C- Money lost from a pocket

Step-by-step explanation:

It would be C because something is decreasing ( now a negative) from what they did have.

4 0

3 years ago

Carmen had one third cup of sugar for 3 pitchers of fruit juice . She poured the same amount of sugar into each pitcher .how muc

butalik [34]

Answer:

Step-by-step explanation:

6 0

2 years ago

A store sold 2.5 times as many footballs as basketballs last year. What is the number of footballs sold for every basketball sol

bixtya [17]

Answer:

Step-by-step explanation:

You aren't able to figure out an exact number of either footballs or basketballs because you don't have enough information for that, but you do have enough to get an expression for one in terms of the other, which I imagine is the point here. We know that for every 1 basketball sold, we sold 2.5 footballs, so the algebraic expression for that is

1 bball = 2.5 fballs

This gives us the number of bballs in terms of fballs but we want the number of fballs in terms of bballs, so solve that expression for fballs:

1 fball = 1/2.5 bballs

or, in words, for every single football sold, 2/5 of a basketball was sold. Sounds silly, but I think your teacher is trying to get you to figure out how to express one thing in terms of another so you can use the expressions in solving story problems.

6 0

3 years ago

In a widget factory, machines A, B, and C manufacture, respectively, 20, 30, and 50 percent of the total. Of their output 6, 3,

steposvetlana [31]

Answer:

38.71% probability it was manufactured by machine A.

29.03% probability it was manufactured by machine B.

32.26% probability it was manufactured by machine C.

Step-by-step explanation:

We have these following probabilities:

A 20% probability that the chip was fabricated by machine A.

A 30% probability that the chip was fabricated by machine B.

A 50% probability that the chip was fabricated by machine C.

A 6% probability that a chip fabricated by machine A was defective.

A 3% probability that a chip fabricated by machine B was defective.

A 2% probability that a chip fabricated by machine C was defective.

The question can be formulated as:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What are the probabilities that it was manufactured by machines A, B, and C?

Machine A

What is the probability that the widget was manufactures by machine A, given that it is defective?

P(B) is the probability that it was manufactures by machine A. So $P(B) = 0.20$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine A. So $P(A/B) = 0.06$

P(A) is the probability that a widget is defective. This is the sum of 6% of 20%, 3% of 30% and 2% of 50%. So

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.2*0.06}{0.031} = 0.3871$

38.71% probability it was manufactured by machine A.

Machine B

What is the probability that the widget was manufactures by machine B, given that it is defective?

P(B) is the probability that it was manufactures by machine B. So $P(B) = 0.30$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine B. So $P(A/B) = 0.03$

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.03}{0.031} = 0.2903$

29.03% probability it was manufactured by machine B.

Machine C

What is the probability that the widget was manufactures by machine C, given that it is defective?

P(B) is the probability that it was manufactures by machine C. So $P(B) = 0.50$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine C. So $P(A/B) = 0.02$

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.02}{0.031} = 0.3226$

32.26% probability it was manufactured by machine C.

6 0

3 years ago