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Darina [25.2K]
2 years ago
14

02. Using Tables 1 to 3, what pattern do you observe in terms of the phase and number of carbon atoms of the alkanes, alkenes, a

nd alkynes?​

Chemistry
1 answer:
BabaBlast [244]2 years ago
5 0

Hey there mate ;), Im Benjemin and lets solve your question.

★ (Alkanes) : forms single bonds between carbon atoms.

The first four elements are gases and others are liquid in state.

★(Alkenes) : forms double bonds between carbon atoms.

The first three alkenes are gases and rest are liquid.

★ (Alkynes) : forms triple bonds between carbon atoms.

First three are gases and the last one is liquid.

According to boiling point :

The larger structure of the hydrocarbons, the higher the boiling points they have.

In the 3 tables, we can see that the boiling point increases.

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The types of nuclear reactions are fission , fusion , what else
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What type of reaction is : CaCo3+ HCl = CaCl2 + CO2 +H2O
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Answer:

Double decomposition reaction

Explanation:

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Different isotopes of the same element emit light at slightly different wavelengths. A wavelength in the emission spectrum of a
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Different isotopes of the same element emit light at slightly different wavelengths, the minimum number of slits  is mathematically given as

N=1820slits

<h3>What minimum number of slits is required to resolve these two wavelengths in second-order?</h3>

Generally, the equation for the wave is mathematically given as

d\ sin\ (\theta\ m) \ = \ m\  \lambda

Where the chromatic resolving power (R) is defined by

R\  =\ \lambda\ / \ d \  \lambda

R = nN,

Therefore

\lambda_1 \ = \  (656.45)(1 \ * \ 10^{-9})/1mm

\lambda_1= 656.45*10^{-9}

and

\lambda_2= (656.27)(1*10^{-9})/1mm

\\\\\lambda_2= 656.27*10^{-9}m

In conclusion, the minimum number of slits is required to resolve these two wavelengths in second-order

N\ =\ \dfrac{\lambda}{m\ d\ T\ }\\\\

Therefore

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N=1820slits

Read more about slits

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