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Ierofanga [76]
3 years ago
11

Describe the three steps of solution formation. be sure to include the details regarding the dissolving of the substance

Chemistry
2 answers:
Elza [17]3 years ago
8 0

The three steps involve;

Step 1: Separation/expansion of the solute particles

Step 2: Separation/expansion of the solvent particles

Step 3; Combining the solute and solvent particles


The first two steps are usually endothermic. Step 3, nonetheless, can be either exothermic or endothermic and is significant in determining whether the dissolving process will be endothermic or exothermic.


IceJOKER [234]3 years ago
8 0

Answer:

The dissolution process is carried out in three completely independent stages:

1. Separation of solvent molecules

2. Separation of solute molecules.

3. Mixture of solvent and solute molecules.

Explanation:

A solution occurs when the solute and solvent molecules meet by intermolecular attractions, which should not be interpreted as chemical bonds. When a substance dissolves in another substance, the solute particles spread over the solvent. These particles break into positions occupied by solvent molecules. Its ease of replacement is dependent on the strength of three interactions: between solvent and solvent, between solute and solute, and between solvent and solute.

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What is the pH of a 0.40 M solution of C6H5COOH?
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3 years ago
The equilibrium concentrations of the reactants and products are [HA]=0.280 M, [H+]=4.00×10−4 M, and [A−]=4.00×10−4 M. Calculate
Tems11 [23]

Answer:

6.24

Explanation:

The following data were obtained from the question:

Concentration of HA, [HA] = 0.280 M,

Concentration of H+, [H+] = 4×10¯⁴ M

Concentration of A-, [A−] = 4×10¯⁴ M

pKa =.?

Next, we shall write the balanced equation for the reaction. This is given below:

HA <===> H+ + A-

Next, we shall determine the equilibrium constant Ka for the reaction. This can be obtained as follow:

Equilibrium constant for a reaction is simply the ratio of concentration of the product raised to their coefficient to the concentration of the reactant raised to their coefficient.

The equilibrium constant for the above equation is given below:

Ka = [H+] [A−] /[HA]

Concentration of HA, [HA] = 0.280 M,

Concentration of H+, [H+] = 4×10¯⁴ M

Concentration of A-, [A−] = 4×10¯⁴ M

Equilibrium constant (Ka) =

Ka = (4×10¯⁴ × 4×10¯⁴) / 0.280

Ka = 1.6×10¯⁷/ 0.280

Ka = 5.71×10¯⁷

Therefore, the equilibrium constant for the reaction is 5.71×10¯⁷

Finally, we shall determine the pka for the reaction as follow:

Equilibrium constant, Ka = 5.71×10¯⁷

pKa =?

pKa = – Log Ka

pKa = – Log 5.71×10¯⁷

pKa = 6.24

Therefore, the pka for the reaction is 6.24.

6 0
3 years ago
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Answer:

Atoms must have similar electronegativities in order to share electrons in a covalent bond.

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When atoms of different electronegativities combine, the more electronegative atom pulls more electrons towards itself, hence, an IONIC bond is formed. However, when the electronegativities of the atoms are similar, the sharing of their electrons becomes stronger. Hence, ATOMS MUST HAVE SIMILAR ELECTRONEGATIVITIES in order to share electrons in a covalent bond.

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