Answer:
Explanation:
Given
Initial velocity of ball
height of window
Using Equation of motion
where u=initial velocity
t=time
a=acceleration
As ball is already is at a height of 20 m so
(b)highest point is obtained at v=0
where
v=final velocity
u=initial velocity
a=acceleration
s=displacement
Highest Point will be
(c)Time taken when the ball hit the ground i.e. at Y=0
impact velocity
Answer:
Velocity = 0.4762 m/s
Explanation:
Given the details for the simple harmonic motion from the question as:
Angular frequency, ω = 12 rad/s
Amplitude, A = 0.060 m
Displacement, y = 0.045 m
The initial Energy = U = (1/2) kA²
where A is the amplitude and k is the spring constant.
The final energy is potential and kinetic energy
K + U = (1/2) mv² + (1/2) kx²
where x is the displacement
m is the mass of the object
v is the speed of the object
Since energy is conservative. So, the final and initial energies are equal as:
(1/2) k A² = (1/2) m v² + (1/2) kx²
Using, ω² = k/m, we get:
Velocity:
<u>Velocity = 0.4762 m/s</u>
Explanation:
Hope its helps u
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