1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
guajiro [1.7K]
3 years ago
12

Which is NOT a property of gold? Select one: a. rare b. malleable c. tarnishes d. corrosion resistant

Physics
2 answers:
lara31 [8.8K]3 years ago
6 0

c because gold does not tarnish

irakobra [83]3 years ago
5 0
If I'm correct, gold does not tarnish so C.
You might be interested in
A girl rides her scooter to school, a total distance of 4.5km. She has to slow down twice to cross busy streets, but overall the
Whitepunk [10]

Answer:

6.93 km/h

Explanation:

To calculate her average speed, we need the "speed" formula, which is:

average speed = distance / time

You plug in your numbers and it will give you the answer.

Speed = 4.5km/0.65hr

           = 6.923 km/h

8 0
3 years ago
Read 2 more answers
What is used to create the sequential order of elements?
algol [13]
Atomic Number
or
Number of Protons

ΩΩΩΩΩΩΩΩΩΩ
5 0
2 years ago
Read 2 more answers
A quarterback throws a football toward a receiver with an initial speed of 20 m/s at an angle of 30∘ above the horizontal. At th
lana66690 [7]

Answer:

a) In order to catch the ball at the level at which it is thrown in the direction of motion.

b)Speed of the receiver will be 7.52m/s

Explanation:

Calculating range,R= Vo^2Sin2theta/g

R= (20^2×Sin(2×30)/9.8 = 35.35m

Let receiver be(R-20) = 35.35-20= 15.35m

The horizontal component of the ball is:

Vox= Vocostheta= 20× cos30°

Vox= 17.32m/s

Time taken to coverR=35.35m with 17.32m/s will be:

t=R/Vox= 35.35/17.32

t= 2.04seconds

b)Speed required to cover 15.35m at 2.04seconds

Vxreciever= d/t = 15.35/2.04 = 7.52m/s

7 0
2 years ago
Read 2 more answers
Explain the application of pascals law<br>​
Marta_Voda [28]

Answer:

pplications of Pascal’s Law  

Hydraulic Lift: The image you saw at the beginning of this article is a simple line diagram of a hydraulic lift. This is...

The construction is such that a narrow cylinder (in this case A) is connected to a wider cylinder (in this case B). They...

Pressure applied at piston A is transmitted equally to piston B without diminishing, on use of an incompressible fluid.

Explanation:

6 0
3 years ago
How much does a crate weigh (force) if it is 0.25 meters wide and 1.5 meters long and it
serg [7]

Force of a crate : 300 N

<h3>Further explanation</h3>

Given

0.25 meters wide and 1.5 meters long

Pressure = 800 Pa

Required

Force

Solution

P = F/A

A = 0.25 x 1.5

A = 0.375 m²

P = 800 Pa = 800 N/m²

Input the value :

F = P x A

F = 800 N/m² x 0.375 m²

F = 300 N

6 0
3 years ago
Other questions:
  • A note is being played on a string on a guitar. The string is then pushed to the side while still in contact with the same fret.
    14·1 answer
  • A pulley is used to lift a heavy mass from the floor to the platform. The IMA of the system is 5 and the AMA is 2.5. What is the
    15·2 answers
  • Help! Please???
    5·1 answer
  • Two lab partners, Mary and Paul, are both farsighted. Mary has a near point of 68.6 cm from her eyes and Paul has a near point o
    15·1 answer
  • Atoms with the same number of protons but with different electrical charges _____.
    9·2 answers
  • An electron of mass 9.11*10-31kg has an initial speed of 3.00*105m/s. It travels in a straight line and its speed increases to 7
    9·1 answer
  • If a train travels at a constant 18.0 m/s, how far would it move in one hour? In 1.00 minute? In 1.00 second?
    11·1 answer
  • Please help me i need some help!!
    5·1 answer
  • 1.Una partícula de masa m = 0.2 [kg] está unido a dos resortes idénticos (de longitud L = 1.2 [m]) sobre la parte superior de un
    14·1 answer
  • Identify the origins of breakdown when using a spectrum analyzer
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!