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Y_Kistochka [10]
3 years ago
14

how will resistance change when the voltage increases in an electric circuit if the current remains constant

Physics
1 answer:
Yakvenalex [24]3 years ago
3 0
V=IR
Potential Difference (v)= Current (A) * Resistance (Ω)
As V increases, R also increases.
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Which of these is a unit of heat? <br> a. joule <br> b. degree celsius <br> c. kelvin <br> d. tesla
attashe74 [19]

-- Heat is a form of energy.
-- Joule is the SI unit of energy.
ergo
-- Joule is a unit of heat.

'Degree Celsius' and 'Kelvin' are units of temperature.
Heat and temperature are different things.
We won't go there right now.
3 0
3 years ago
S the work done on Amanda's car while speeding up (i) greater than, (ii) less than, or (iii) the same as the work done on Bertha
ankoles [38]

Answer:

Explanation:

Mass of amanda and bertha car = Ma = Mb

Initial velocity of amanda, ua = 10 m/s

Final velocity of amanda, va = 20 m/s

Initial velocity of bertha, ub = 20 m/s

Final velocity of bertha, vb = 30 m/s

Workdone = change in Energy = 1/2 mv^2 - 1/2 mu^2

Ea = Ma × 1/2 × (20^2 - 10^2)

= Ma × 150

= 150 Ma J

Workdone = change in Energy = 1/2 mv^2 - 1/2 mu^2

Eb = Mb × 1/2 × (30^2 - 20^2)

= Mb × 250

= 250 Mb J

Option ii. Less than. Thus this is because the workdone by amanda car (150Ma) is less than the workdone in berthas car (250Mb).

B.

Impulse, p = force × time

p = Mass × change in velocity

pa = Ma × va - Ma × ua

= Ma × (20 - 10)

= 10 × Ma

= 10 Ma

p = Mass × change in velocity

pa = Mb × vb - Mb × ub

= Mb × (30 - 20)

= 10 × Mb

= 10 Mb

Option iii. The same as.

The impulse as seen above is the same in amanda car (10Ma) as the same with bertha (10Mb)

7 0
4 years ago
MULTIPLE CHOICE PLEASE HELP QUICK!!!!!!
vekshin1
 i would choose a for 945 and a for faster
5 0
3 years ago
Read 2 more answers
A source vibrating at constant frequency generates a sinusoidal wave on a string under constant tension. If the power delivered
Serjik [45]

Answer:

n = 1,732    the amplitude must be increased by a factor of 1,732

Explanation:

The power delivered by a wave is given by

                  P = E / t

                  P = ½ μ w² v A²

let's apply this expression to our case the power tripled

                3P₀ = ½ μ w² v A’²

                 

let's write the amplitude function of a initial amplitude

               A ’= n A₀

where n is a number

               3 P₀ = (½ μy w² v  A₀²) n²

               3P₀ = P₀ n²

               n = √ 3

               n = 1,732

therefore the amplitude must be increased by a factor of 1,732

4 0
3 years ago
‼️DEADLINE 10:30‼️HELP‼️​
sashaice [31]
I forgot the answer
4 0
3 years ago
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