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3 years ago

how will resistance change when the voltage increases in an electric circuit if the current remains constant

Physics

1 answer:

Yakvenalex [24]3 years ago

3 0

V=IR
Potential Difference (v)= Current (A) * Resistance (Ω)
As V increases, R also increases.

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Which of the following represent units of an electric field? select all that apply

zimovet [89]

Answer:

Volts/Meter

Newtons/Coulomb

Explanation:

Volts/ Meter and Newtons/Coulomb both are same and the units of Electric field intensity or electric field strength.

Electric field strength E is the force per unit charge. It is measured in Newton/Coulomb in SI unit. It is a vector quantity directed in the direction of force.

Mathematically,

Electric field strength = Force/Charge

E = F / q₀

= Newton / Coulomb = NC⁻¹ 1

We know that

Newton = Joule/meter 2

Also

Volt = Joule/Coulomb 3

So put 3 in 2 we get

Newton = (Volt Coulomb)/meter put in 1

E = (Volt Coulomb)/(meter Coulomb)

= Volt / meter

Hence

Newton / Coulomb = Volt / meter

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The psychologist known for latent learning and cognitive maps is _________. A. Robert Rescorla B. Edward Tolman C. William James

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Answer:

Explanation:

B. Edward Tolman

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Sino ang legendary hacker ng pilipinas?

suter [353]

Answer:

Onel de guzman now he's 44,the first world's computer virus has admitted to his guilt.

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3 years ago

You are sitting on a merry-go-round of mass 200 kg and radius 2m that is at rest (not spinning). Your mass is 50 kg. Your friend

Bogdan [553]

Answer:

a. $\tau=200J$ b. $\alpha=0.44 \frac{rad}{s^2}$ c. $\alpha=0.33\frac{rad}{s^2}$ d. The angular acceleration when sitting in the middle is larger.

Explanation:

a. The magnitude of the torque is given by $\tau=rF\sin \theta$ , being r the radius, F the force aplied and $\theta$ the angle between the vector force and the vector radius. Since $\theta=90^{\circ}, \, \sin\theta=1$ and so $\tau=rF=2m100N=200Nm=200J$ .

b. Since the relation $\tau=I\alpha$ hols, being I the moment of inertia, the angular acceleration can be calculated by $\alpha=\frac{\tau}{I}$ . Since we have already calculated the torque, all left is calculate the moment of inertia. The moment of inertia of a solid disk rotating about an axis that passes through its center is $I=\frac{1}{2}Mr^2$ , being M the mass of the disk. If we assume that a person has a punctual mass, the moment of inertia of a person would be given by $I_p=m_pr_p^{2}$ , being $m_p$ the mass of the person and $r_p^{2}$ the distance from the person to the center. Given all of this, we have

$\alpha=\frac{\tau}{I}=\frac{\tau}{I_{disk}+I_{person}}=\frac{Fr}{\frac{1}{2}Mr^2+m_pr_p^{2}}=\frac{200Nm}{\frac{1}{2}200kg*4m^2+50kg*1m^2}=\frac{200\frac{kgm^2}{s^2}}{450Nm^2}\approx 0.44\frac{rad}{s^2}$ .

c. Similar equation to b, but changing $r_p=2m$ , so

$alpha=\dfrac{200\frac{kgm^2}{s^2}}{\frac{1}{2}200*4kg\,m^2+50*4 kg\,m^2}=\dfrac{200}{600}\dfrac{1}{s^2}\approx 0.33 \frac{rad}{s^2}$ .

d. The angular acceleration when sitting in the middle is larger because the moment of inertia of the person is smaller, meaning that the person has less inertia to rotate.

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The movement of air around an anticyclone is:

N76 [4]

Pretty sure it is clockwise if I am not mistaken

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