Question 8 (1 point)

if the Horse and Rider have a combined mass of 572 kg what force would be required to accelerate them 5 kph per second

Vlad [161]

Answer:

Force required to accelerate = 794.44 N

Explanation:

Force required = Mass of horse x Acceleration of horse

Mass of horse and rider, m= 572 kg

Acceleration of horse and rider, a = 5 kph per second

$=\frac{5*1000}{60*60} =1.39 m/s^2$

Force required = ma

= 572 x 1.39 = 794.44 N

Force required to accelerate = 794.44 N

8 0

3 years ago

What is Br charge after it gains an electron?

sergeinik [125]

Im not 100% sure but i think its bromine.

Hope this helps ^_^

4 0

2 years ago

observe the figure given carefully volume of water in each vessel is shown arrange them in order of decreasing pressure at the b

mihalych1998 [28]

Answer:

See the explanation below

Explanation:

The pressure is defined as the product of the density of the liquid by the gravitational acceleration by the height, and can be easily calculated by means of the following equation.

$P=Ro*g*h$

where:

Ro = density of the fluid [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation [m]

In this way we can understand that the greater pressure is achieved by means of the height of the liquid, that is, as long as the fluid has more height, greater pressure will be achieved at the bottom.

Therefore in order of decreasing will be

The largest pressure with the largest height of the liquid, container B. The next is obtained with container D, the next with container A and the lowest pressure with container C.

The pressure decreases as we go from the container B - D - A - C

5 0

3 years ago

4. With a diameter that's 11 times larger than Earth's, _______ is the largest planet.

Komok [63]

The answer is B.Jupiter

7 0

2 years ago

A commuter train passes a passenger platform at a constant speed of 40.4 m/s. The train horn is sounded at its characteristic fr

mihalych1998 [28]

(a) -83.6 Hz

Due to the Doppler effect, the frequency of the sound of the train horn appears shifted to the observer at rest, according to the formula:

$f' = (\frac{v}{v\pm v_s})f$

where

f' is the apparent frequency

v = 343 m/s is the speed of sound

$v_s$ is the velocity of the source of the sound (positive if the source is moving away from the observer, negative if it is moving towards the observer)