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jok3333 [9.3K]
3 years ago
14

Barometers have long been used to predict the weather. Jay and Jeff were responsible for recording the class weather data each d

ay in March. One day, they noticed that there was a rapid change in the barometric pressure. The barometric pressure dropped down very, very quickly. What type of weather could Jay and Jeff expect soon? A) fog B) rain C) clearing D) drop in temperature
Physics
2 answers:
g100num [7]3 years ago
7 0

Answer:

B) rain

Explanation:

The barometer is a device that is used to measure atmospheric pressure and, consequently, the height at which someone rises, as well as to approximately predict atmospheric changes. Thus, a rising barometer indicates an increase in air pressure, whereas a falling barometer indicates a decrease in air pressure.

In environments with low atmospheric pressure and, therefore, heat, the heated air tends to rise and, when reaching higher altitudes, condenses, forms clouds and precipitates. In this situation, the barometric pressure drops very, very quickly, indicating that a rain is coming.

AfilCa [17]3 years ago
4 0

Answer:

B

Explanation:

You would have rain. You would have clouds, precipitation, and strong winds.

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The alpha line in the balmer series of the hydrogen spectrum consists of light having a wavelength of 6.56. calculate the freque
guajiro [1.7K]
The alpha line in the Balmer series is the transition from n=3 to n=2 and with the wavelength of λ=656 nm = 6.56*10^-7 m. To get the frequency we need the formula: v=λ*f where v is the speed of light, λ is the wavelength and f is the frequency, or c=λ*f. c=3*10^8 m/s. To get the frequency: f=c/λ. Now we input the numbers: f=(3*10^8)/(6.56*10^-7)=4.57*10^14 Hz. So the frequency of the light from alpha line is f= 4.57*10^14 Hz. 
5 0
3 years ago
Why can you see your own reflected image in a mirror but not on a dry, painted wall?
kaheart [24]
A wall uses diffuse reflection while a mirror uses specular reflection. For example, when parallel light rays enter a mirror, they remain parallel when exiting the mirror, allowing you to see a reflection of the light rays. On the contrary, when incident light rays enter a wall which is painted, the rays scatter, not allowing you to see anything but a painted wall. 
7 0
3 years ago
High-speed stroboscopic photographs show that the head of a 210-g golf club is traveling at 56 m/s just before it strikes a 46-g
tamaranim1 [39]

Explanation:

It is given that,

Mass of golf club, m₁ = 210 g = 0.21 kg

Initial velocity of golf club, u₁ = 56 m/s

Mass of another golf ball which is at rest, m₂ = 46 g = 0.046 kg

After the collision, the club head travels (in the same direction) at 42 m/s. We need to find the speed of the golf ball just after impact. Let it is v.

Initial momentum of golf ball, p_i=m_1u_1=0.21\ kg\times 56\ m/s=11.76\ kg-m/s

After the collision, final momentum p_f=0.21\ kg\times 42\ m/s+0.046v

Using the conservation of momentum as :

p_i=p_f

11.76\ kg-m/s=0.21\ kg\times 42\ m/s+0.046v

v = 63.91 m/s

So, the speed of the  golf ball just after impact is 63.91 m/s. Hence, this is the required solution.

3 0
3 years ago
PLEASE HELP, LOOK AT PHOTO PLZ!!!
PIT_PIT [208]

Answer:

a) 17 km

b) 9 km

Explanation:

The distance is the length of the path.

A to C: 5 km

B to C: 4 km

C to B: 4 km

B to C: 4 km

Total distance = 5 km + 4 km + 4 km + 4 km = 17 km

Displacement is the difference between the starting point and ending point.

Displacement = 9 km − 0 km = 9 km

3 0
3 years ago
Older televisions display a picture using a device called a cathode ray tube, where electrons are emitted at high speed and coll
Len [333]

Answer:

Explanation:

initial velocity v = 2.1  x 10⁷ m/s

acceleration a = 5.1 x 10¹⁵ m /s²

horizontal distance covered = 5.5 x 10⁻² m

time taken to cover horizontal distance =  5.5 x 10⁻² / 2.1  x 10⁷

= 2.62 x 10⁻⁹ s .

b )

vertical distance travelled due to vertical acceleration

= 1/2 a t²

= .5 x 5.1 x 10¹⁵ x (2.62 x 10⁻⁹)²

= 17.5 x 10⁻³ m

4 0
3 years ago
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