Answer:
102597.6 Pa
Explanation:
mass, m = 1.25 g
Force, F = m x g = 1.25 x 9.8 x 10^-3 = 0.01225 N
radius, r = 0.195 mm = 0.195 x 10^-3 m
Area, A = πr² = 3.14 x 0.195 x 0.195 x 10^-6 m^2
A = 1.19 x 10^-7 m^2
Pressure is defined as the thrust acting per unit area.
P = Force / Area
P = 0.01225 N / (1.10 x 10^-7)
P = 102597.6 Pa
Thus, the pressure exerted is 102597.6 Pa.
You just need the energy of turning of water in to steam. Water is a little funny because once water gets to 100 degrees C, it stops changing in temperature whilst it all turns to steam. The amount of energy required to turn 1 gram of water into steam is 2257 Joules. We call this the latent heat of vaporisation. So to turn 74.6 grams of water to steam, you would need:
2257J/gram x 74.6g = 168,372.2 J = 168.4 kJ
(<span></span><em>latent heat of vaporisation: 2257 J/gram</em>)
As the headwind comes at the head of the plane, therefore 50 mph headwind slows the plane down.
Thus actual speed of plane with headwind, 
Now using the formula , 



Hence plane will take time to complete the distance 1250 mile in 2.5 hours
Answer: 1.51 km
Explanation:
<u>Coulomb's Law:</u> The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.
Or, 
Where Q1 and Q2 are magnitude of two charges and r is distance between them:
<u>Given:</u>
Q1 = Charge near top of cloud = 48.8 C
Q2 = Charge near the bottom of cloud = -41.7 C
Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N
k = 8.99 x 109Nm^2/C^2
<u>So,</u>

Therefore, the separation between the two charges (r) = 1.51 km
Answer:
I believe it's A. Cold Front.
Hope this helps, Mark as brainiest please. :-)