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WARRIOR [948]
3 years ago
14

Find the domain: { (2, 1) , (6, 4) , (7, 7) , (7, 10) }

Mathematics
2 answers:
kicyunya [14]3 years ago
8 0
The answers is:
D={2,6,7}
You know that it is the domain because it is at the beginning of the parenthesis and is always x.
(x,y) if you were looking for y you would be looking for the second number in the parenthesis and that is know as range.
Usimov [2.4K]3 years ago
5 0
2, 6, and 7 are the domain because they are in the "x" spot

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approximate the integral 0 to pi/2 xsin(x)dx by computing the Left and Right sums, using the parition (0, pi/6, pi/4, pi/3, pi/2
Cerrena [4.2K]
3.14 times all will give you the answer
8 0
3 years ago
I need some help, please help. I have been stuck on this for days.
dlinn [17]

Answer:

Angle CDE equals 155 degrees :D

Step-by-step explanation:

parallel lines

since the left angle is 57, angle BAE is also 57

180-57=123

right angle=90

115+90+123+57=385

540-385=155

thus, angle CDE equals 155 degrees

5 0
2 years ago
Read 2 more answers
Consider these dimensions for a cylindrical aquarium.
vagabundo [1.1K]

The amount of water that will fill the tank is 11100 cu.ft to the nearest hundredth.

<h3>What is a Cylindrical figure ?</h3>

A cylinder is a three dimensional figure with two identical circular faces at each end , and a curved surface.

It does not have an edges or vertices.

It is given in the question that

A cylinder with height 14 feet and radius 25 feet.

The volume of a cylinder.

V = π252(14)

The water than can be filled is equal to the volume of the cylinder

V = 11088 cu.ft

There  the amount of water that will fill the tank is 11100 cu.ft to the nearest hundredth.

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6 0
2 years ago
Easy points easy points
tatyana61 [14]
4 outta 16 or 4/16 I think
8 0
3 years ago
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Simplify the following expression. 4 to -11/3 power ÷ 4 to -2/3 power
nignag [31]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4^{-\frac{11}{3}}\div 4^{-\frac{2}{3}}\implies \cfrac{4^{-\frac{11}{3}}}{4^{-\frac{2}{3}}}\implies 4^{-\frac{11}{3}}\cdot 4^{\frac{2}{3}}\implies 4^{-\frac{11}{3}+\frac{2}{3}} \\\\\\ 4^{-\frac{9}{3}}\implies 4^{-3}\implies \cfrac{1}{4^3}\implies \cfrac{1}{64}

3 0
4 years ago
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