Answer:
The force exerted by the block on the floor is 38.4 Newtons
Explanation:
The given parameters are;
The area of the box in contact with the floor, A = 2.4 m²
The pressure exerted by the block on the floor, P = 16 N/m²
The force exerted by the box on the floor is given as follows;
∴ F = P × A
From the question, P = 16 N/m², and A = 2.4 m²
∴ F = 16 N/m² × 2.4 m² = 38.4 N
The force exerted by the block on the floor, F = 38.4 N.
Answer:
D
Explanation:
From the information given:
The angular speed for the block
Disk radius (r) = 0.2 m
The block Initial velocity is:
Change in the block's angular speed is:
However, on the disk, moment of inertIa is:
The time t = 10s
∴
Frictional torques by the wall on the disk is:
Finally, the frictional force is calculated as:
Answer:
Check the explanation
Explanation:
From given data, it can be noted that 95% of given confidently data, means 5% of data is uncertain. According to the question, we have to calculate uncertainty in Cp .
Kindly check the attached image below for the step by step explanation to the question above.
