A box is placed on the floor.The area of the box in contact with the floor is 2.4m²Pressure exerted on the floor 16 newtons/m²Wo
1 answer:
Answer:
The force exerted by the block on the floor is 38.4 Newtons
Explanation:
The given parameters are;
The area of the box in contact with the floor, A = 2.4 m²
The pressure exerted by the block on the floor, P = 16 N/m²
The force exerted by the box on the floor is given as follows;
∴ F = P × A
From the question, P = 16 N/m², and A = 2.4 m²
∴ F = 16 N/m² × 2.4 m² = 38.4 N
The force exerted by the block on the floor, F = 38.4 N.
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Answer:
The magnitude of the large object's momentum change is 3 kilogram-meters per second.
Explanation:
Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:
(1)
Where:
,
- Initial and final momemtums of the small object, measured in kilogram-meters per second.
,
- Initial and final momentums of the big object, measured in kilogram-meters per second.
If we know that ,
and
, then the final momentum of the big object is:
The magnitude of the large object's momentum change is:
The magnitude of the large object's momentum change is 3 kilogram-meters per second.
Answer:
42 m/s
Explanation:
by definition of the velocity(speed) of a wave,
The velocity of light, v, is the product of its wavelength, λ , and its frequency, f.
V= fλ
frequency - number of occurances in a unit time
(check the graph)
