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3 years ago

Which type of molecule is added to this genetic sequece might create a insertion mutation? A-G-A-T-G-C-A-G-A-G-T-T-A-C-G-G

1 answer:

3 0

D. Adding another base pair will re-arrange your DNA sequences and cause an insertion mutation. This will make your codons group of differently, and possibly give you a BAD mutation. However, sometimes the codons still make the same proteins as its supposed to, the mutation will NOT affect you.

Example:

THE BIG FAT CAT ATE THE RAT

Now, if i were to add a letter (X) to this and make the letters group up in three aka the codons:

THE XBI GFA TCA TAT ETH ERA T

As you can you can see, adding a base pair in a DNA insertion will usually have a negative effect, specifically a insertion mutation.

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Select the correct answer what is meditation

german

Answer:

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2 years ago

Two square air-filled parallel plates that are initially uncharged are separated by 1.2 mm, and each of them has an area of 190

julia-pushkina [17]

Answer:

$5.5\cdot 10^{-11} C$

Explanation:

The capacitance of the parallel-plate capacitor is given by:

$C=\epsilon_0 \frac{A}{d}$

where

$\epsilon_0 = 8.85\cdot 10^{-12} F/m$ is the vacuum permittivity

$A=190 mm^2 = 190 \cdot 10^{-6} m^2$ is the area of the plates

$d=1.2 mm = 0.0012 m$ is the separation between the plates

Substituting,

$C=(8.85\cdot 10^{-12}) \frac{190 \cdot 10^{-6}}{0.0012}=1.4\cdot 10^{-12}F$

The energy stored in the capacitor is given by

$U=\frac{Q^2}{2C}$

Since we know the energy

$U=1.1 nJ = 1.1 \cdot 10^{-9} J$

we can re-arrange the formula to find the charge, Q:

$Q=\sqrt{2UC}=\sqrt{2(1.1\cdot 10^{-9} J)(1.4\cdot 10^{-12}F )}=5.5\cdot 10^{-11} C$

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2 years ago

Why is it advantageous to have two Eyes?

Andru [333]

Answer:para enxergar

Explanation:

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2 years ago

In which changes of state do atoms lose energy

Anika [276]

Yeah, it's every state. Atoms need a certain quanta of energy to jump to each state of energy, and therefore change state depending on how much energy is absorbed and/or released. This applies to all states of matter.

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2 years ago

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The answer is A

Explanation:
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