Answer:
Proved
Step-by-step explanation:
Given: EC || AC, DB || AC, ∠A = ∠F
Prove: ΔMDF ∼ ΔNCA
Solution
See diagram attached to the solution to better understand the following workings.
Redrawing ΔMDF or rotating to be facing the same direction.
EC is parallel to AC
DB parallel to AC
Using similar triangle theorem:
If ΔMDF ∼ ΔNCA
Ratio of Corresponding sides would be equal
(adjacent of ΔMDF)/(adjacent of ΔNCA) = (Opposite of ΔMDF)/(opposite of ΔNCA) = (hypotenuse of ΔMDF)/(hypotenuse of ΔNCA)
DF/ CA = MD/NC = FM/AN
∠A = ∠F
∠M = ∠N
∠D = ∠C
Since the ratio of Corresponding sides and angle are equal, ΔMDF is similar to ΔNCA.
ΔMDF ∼ ΔNCA
Answer:
6/5
Step-by-step explanation:
m is your rate of change you need to get y by itself.
3/2x - 15 = 5/4y
3x/2 - 30/2 = 5/4y
3x-30/2 = 5/4y
3x - 30 = 2 x 5/4y
3x - 30 = 2 x 5/4x2y (cross out 2 and 4)
3x - 30 = 5/2y
2 x 3x - 2 x 30 = 2 x 5/4y
6x - 60 = 5y
6x/5 - 60/5 = 5y/5
y = 6/5 x x - 12
The radius of a circle is half the length of the diameter so
radius=1.5m
Option (A) : least: 10 hours; greatest: 14 hours
The function f(x) = sin x has all real numbers in its domain, but its range is
−1 ≤ sin x ≤ 1.
How to solve such range questions?
Such questions in which every term is in addition and its range is asked is simplest ones to solve if we know the range of each of term. This can be seen from this question
Given: d(t) = 2sin(xt) + 12
= −1 ≤ sin (xt) ≤ 1.
= −2≤ 2 sin (xt) ≤ 2.
= 10 ≤ 2sin (xt) + 12 ≤ 14
= 10 ≤d(t) ≤ 14
Thus least: 10 hours; greatest: 14 hours
Learn more about range of trigonometric ratios here :
brainly.com/question/14304883
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i hope i have been useful buddy.
good luck ♥️♥️♥️♥️♥️.
