Answer:
than look inside it
Explanation:
well if you need to inspect something, looking is very important
Answer:
the minimum shaft diameter is 35.026 mm
the maximum shaft diameter is 35.042mm
Explanation:
Given data;
D-maximum = 35.020mm and d-minimum = 35.000mm
we have to go through Tables "Descriptions of preferred Fits using the Basic Hole System" so from the table, locational interference fits H7/p6
so From table, Selection of International Trade Grades metric series
the grade tolerance are;
ΔD = IT7(0.025 mm)
Δd = IT6(0.016 mm)
Also from Table "Fundamental Deviations for Shafts" metric series
Sf = 0.026
so
D-maximum
Dmax = d + Sf + Δd
we substitute
Dmax = 35 + 0.026 + 0.016
Dmax = 35.042 mm
therefore the maximum diameter of shaft is 35.042mm
d-minimum
Dmin = d + Sf
Dmin = 35 + 0.026
Dmin = 35.026 mm
therefore the minimum diameter of shaft is 35.026 mm
Serviceable wheel bearings can be repacked by removing the dust cap and the cotter pin must be replaced with a new one every time it is removed. Therefore, both Tech A and B are correct.
Sealed bearing assemblies are typically prefilled with lubricant. They also make a more reliable and consistent installation process due to the fact that every into comes preset at the proper clearance.
Furthermore, the serviceable wheel bearings can be repacked by removing the dust cap, filling it with grease, and reinstalling it. Also, cotter pin must be replaced with a new one every time it is removed.
Therefore, both tech A and B are correct.
Read related link on:
brainly.com/question/16612086
Sinusoidal oscillator frequency of oscillation is given below.
Explanation:
The criterion for a stable oscillator is given in the equation
l A(jw)β(jw) l ≥ 1
In this task A represents the gain of the amplifier , and
β represents gain/attenuation of the second-order bandpass filter.
This sinusoidal oscillation is a special edge case where the product is equal to one.
So the condition is A-K=1
to obtain the sustained oscillations at the desired frequency of oscillations, the product of the voltage gain A and the feedback gain β must be one or greater than one. In this case, the amplifier gain A must be 3. Hence, to satisfy the product condition, feedback gain β must be 1/3.
