The box plots represent the ages of pennies in two 50-cent rolls. By looking at the plots, Beth says that the two means are abou
t 5 years apart. Which is true about Beth’s statement? A/ She is correct because the medians are 10 years apart, which means the means are half of that, or 5 years apart. B/ She is correct because the maximum ages of the pennies in each set are 5 years apart. C/ She is not correct because the means are both equal to 12. D/ She may not be correct because means cannot be determined from the box plots.
2 answers:
Answer:
The correct option is D
D) She may not be correct because means cannot be determined from the box plots
Step-by-step explanation:
The question is incomplete because the box plots are not attached in the question. I've attached the box plots of this question at the bottom.
The box plot, also know as box and whisker plot, displays only five type of values, which are:
- Minimum value
- First Quartile
- Median
- Third Quartile
- Maximum value
Mean cannot be determined by just lookin at the box plots. To find the mean, we need to know the values of data and total number of values.
As mean cannot be determined from the box plot, correct option is D
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Answer:
x = - 8
Step-by-step explanation:
Calculate m using the slope formula and equate, since parallel lines have equal slopes.
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 4, 5) and (x₂, y₂ ) = (x, - 13)
m = =
and equating
=
( cross- multiply )
9(x + 4) = - 36 ( divide both sides by 9 )
x + 4 = - 4 ( subtract 4 from both sides )
x = - 8
Answer:
where x₁ and x₂ are values in the interval [x,y] respectively
Step-by-step explanation:
Well, first to determine the average rate of change of a function, you should have the interval of the values of x for the function.
So lets assume you have a function;
And the interval as [1,3]
Then the average rate of change for the function f(x) will be;
where x₁ and x₂ are the interval coordinates x,y respectively. In this case x₁=1 and x₂=3
To find the average rate of change in this example will be;