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podryga [215]
3 years ago
13

The box plots represent the ages of pennies in two 50-cent rolls. By looking at the plots, Beth says that the two means are abou

t 5 years apart. Which is true about Beth’s statement? A/ She is correct because the medians are 10 years apart, which means the means are half of that, or 5 years apart. B/ She is correct because the maximum ages of the pennies in each set are 5 years apart. C/ She is not correct because the means are both equal to 12. D/ She may not be correct because means cannot be determined from the box plots.

Mathematics
2 answers:
Jlenok [28]3 years ago
6 0

Answer:

The correct option is D

D) She may not be correct because means cannot be determined from the box plots

Step-by-step explanation:

The question is incomplete because the box plots are not attached in the question. I've attached the box plots of this question at the bottom.

The box plot, also know as box and whisker plot, displays only five type of values, which are:

  1. Minimum value
  2. First Quartile
  3. Median
  4. Third Quartile
  5. Maximum value

Mean cannot be determined by just lookin at the box plots. To find the mean, we need to know the values of data and total number of values.

As mean cannot be determined from the box plot, correct option is D

marin [14]3 years ago
3 0

Answer:

D

Step-by-step explanation:

Box plots do not show the value of the mean.

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Answer:

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Step-by-step explanation:

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Therefore, the population of the city and the suburb in 2002 (two years after) is:

S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\&  \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2

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S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\&  \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]

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