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ddd [48]
3 years ago
11

A heat pump has a coefficient of performance of 4. if the heat pump absorbs 20 cal of heat from the cold outdoors per cycle, how

much heat in cal is expelled into the warm room
Physics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0
A heat pump has a coefficient of performance of 7.05. If the heat pump absorbs 20 cal of heat from the cold outdoors in each cycle, find the heat expelled to the warm indoors. Answer in units of cal. I believe COP (heating mode) : 7.05 and COP = Qh/W Qc = 20 cal so I have to find Qh= ? cal I dont know an equation to put all this together? Please help, thank you.

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Look at the diagram. Emily needs to complete the circuit. What two points should be connected to complete the circuit and make t
pogonyaev

Answer:

The points 2 and 4 should be connected.

Explanation:

To complete the circuit, we need to connect the two points which when connected, encompass the battery and the bulb in the circuit. The points 2 and 4 do the job, since they connect the terminal of the battery and the terminal of the bulb, and thus complete the circuit.

Therefore,  the choice C is correct.

4 0
3 years ago
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1. How many seconds in 1 year?
Nezavi [6.7K]

Answer:

3.154e+7

Explanation:

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Through what vertical height is a 50 N object moved if 250 J of work is done lifting it against the gravitational field of Earth
zimovet [89]

5m

Explanation:

Given parameters:

Weight of object = 50N

Work done in lifting object = 250J

Unknown:

Vertical height = ?

Solution:

The work done on an object is the force applied to lift a body in a specific direction.

   Work done = force x distance

  Weight is a force in the presence of gravity;

  Work done = weight x height of lifting

Height of lifting = \frac{work done }{weight}

 Height of lifting = \frac{250}{50} = 5m

The vertical height through which the object was lifted is 5m

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

6 0
3 years ago
When a 25-kg crate is pushed across a frictionless horizontal floor with a force of 200 N, directed 20 below the horizontal, th
Fofino [41]

Answer:

Option E is correct 310N

Explanation:

Given that the force used to push the crate is F = 200N

The force directed 20° below the horizontal

Mass of crate is m = 25kg

Weight of the crate can be determine using

W = mg

g is gravitational constant =9.8m/s²

W = 25×9.8

W = 245 N

Check attachment. For free body diagram and better understanding

Using newton second law along the vertical axis since we want to find the normal force

ΣFy = m•ay

ay = 0, since the body is not moving in the vertical or y direction

N—W—F•Sin20 = 0

N = W+F•Sin20

N = 245+ 200Sin20

N = 245 + 68.4

N = 313.4 N

The normal force is approximately 310 N to the nearest ten

3 0
3 years ago
Consider two wind turbines, each located in sites with the same wind speed, and each with the same efficiency. Turbine 1 has a r
Alex787 [66]

Answer:

shut up nerd

Exption:

7 0
3 years ago
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