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andrew-mc [135]
3 years ago
5

Suppose the polar bear was running on land instead of swimming. If the polar bear runs at a speed of about 8.3 m/s, how far will

it travel in 10.0 hours?
Physics
1 answer:
olga_2 [115]3 years ago
8 0

Answer:

298800 m

Explanation:

v =  \frac{d}{t}

V=speed

d=distance

t=time

d = vt

Change hours to seconds

It will be 36000s

8.3m/s * 36000s

=298800m

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<span>d = v² / 2μg </span>

<span>d = 8² / 2(0.41)(9.8) </span>

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<span>Note. In your other example μ = 0.46 and v = 4 m/s </span>



<span>d = v² / 2μg </span>




<span>= 4² / 2(0.46)(9.8) </span>

<span>= 8 / (0.46)(9.8) </span>

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Hope i Helped :D
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oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student
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Mass, m = 6.18 kg

Explanation:

Given the following data;

Frequency, F = 10 Hz

Spring constant, k = 250 N/m

We know that pie, π = 22/7

To find the mass, we would use the following formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

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Substituting into the formula, we have;

10 = 1/2 * 22/7 * √250/m

10 = 22/14 * √250/m

Cross-multiplying, we have;

140 = 22 * √250/m

Dividing both sides by 22, we have;

140/22 = √250/m

6.36 = √250/m

Taking the square of both sides, we have;

6.36² = (√250/m)²

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Cross-multiplying, we have;

40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

3 0
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