Question

2.5-1 the individual fly, suppose that the probability of white eyes is 1/4 and the probability of red eyes is 3/4, and that we may treat these observations as independent Bernoulli trials. The probability that at least four flies have to be checked for eye color to observe a white-eyed fly is given by

Answer 1

Answer:

0.0791

Step-by-step explanation:

Given that  the probability of white eyes is 1/4 and the probability of red eyes is 3/4, for an individual fly.

Observations are independent

Let A be finding the white eyed fly and B

finding the red eyed fly

P(A) for any random trial= 0.25 and

P(B) = 0.75

Each trial is independent of the other

The probability that at least four flies have to be checked for eye color to observe a white-eyed fly

=Probability for I, II, III and Iv flies to have red eyes * Prob for 5th fly to have white eye

=$0.75^4(0.25)\\=0.0791$