\left[x \right] = \left[ 5\right][x]=[5]2(x+1)/−2 = 8−2 _________
_________ Simplifying
\left[x \right] = \left[ 2\right][x]=[2] = x + 1 + -4
x = -5
Answer:
The confidence interval for 90% confidence would be narrower than the 95% confidence
Step-by-step explanation:
From the question we are told that
The sample size is n = 41
For a 95% confidence the level of significance is
and
the critical value of
is ![Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }= 1.96](https://tex.z-dn.net/?f=Z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%3DZ_%7B%5Cfrac%7B0.05%20%7D%7B2%7D%20%7D%3D%20%201.96)
For a 90% confidence the level of significance is
and
the critical value of
is ![Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }= 1.645](https://tex.z-dn.net/?f=Z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%3DZ_%7B%5Cfrac%7B0.10%20%7D%7B2%7D%20%7D%3D%20%201.645)
So we see with decreasing confidence level the critical value decrease
Now the margin of error is mathematically represented as
given that other values are constant and only
is varying we have that
![E\ \ \alpha \ \ Z_{\frac{\alpha }{2} }](https://tex.z-dn.net/?f=E%5C%20%5C%20%20%5Calpha%20%5C%20%5C%20%20%20Z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D)
Hence for reducing confidence level the margin of error will be reducing
The confidence interval is mathematically represented as
![\= x - E < \mu < \= x + E](https://tex.z-dn.net/?f=%5C%3D%20x%20%20-%20E%20%20%3C%20%20%5Cmu%20%3C%20%20%5C%3D%20x%20%20%2B%20E)
Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower
Answer:
the regular price was 33.75
Answer:
sorryyyy i dont know the answer :-(
Step-by-step explanation:
sorryy
Answer:
Step-by-step explanation:
(-4,8) & ( -4,2)
![Midpoint=\left(\dfrac{x_{1}+x_{2}}{2},\dfrac{y_{1}+y_{2}}{2} \right)\\\\\\=\left(\dfrac{-4-4}{2},\dfrac{8+2}{2}\right)\\\\\\=\left(\dfrac{-8}{2},\dfrac{10}{2} \right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7Bx_%7B1%7D%2Bx_%7B2%7D%7D%7B2%7D%2C%5Cdfrac%7By_%7B1%7D%2By_%7B2%7D%7D%7B2%7D%20%5Cright%29%5C%5C%5C%5C%5C%5C%3D%5Cleft%28%5Cdfrac%7B-4-4%7D%7B2%7D%2C%5Cdfrac%7B8%2B2%7D%7B2%7D%5Cright%29%5C%5C%5C%5C%5C%5C%3D%5Cleft%28%5Cdfrac%7B-8%7D%7B2%7D%2C%5Cdfrac%7B10%7D%7B2%7D%20%5Cright%29)
= (-4,5)