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kompoz [17]
3 years ago
11

A car has a mass of 1.20 × 103 kilograms and a momentum of 2.00 × 104 kilogram meters/second. What is the velocity of the car?

Physics
2 answers:
patriot [66]3 years ago
8 0
<span>momentem = mass * velocity also, be sure to use the carrot for exponents 10^3 and 10^4. 20000/1200 = 16.7,This is your answer,That was hard lol.



Hope the helps.

</span>
Vera_Pavlovna [14]3 years ago
3 0
We know, Momentum = Mass * velocity 
2 * 10⁴ = (1.20 * 10³) (v)
v = 2 * 10⁴ / 1.20 * 10³
v = 1.67 * 10
v = 16.7 m/s

In short, Your Answer would be Option C

Hope this helps!
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I will answer this in English.

We know that the apple needs 5 seconds to reach the ground.

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a = -g

for the velocity, we integrate the acceleration over time, and as the apple is dropped, we do not have any initial velocity, so we do not have a constant in the integration:

v = -g*t

for the position we integrate again, now we have an initial height H, so the position is:

p = (-g/2)*t^2 + H

now the apple hits the ground when p = 0, so we can solve this equation to find H.

i will use g = 9.8m/s^2

0 = (-4.9m/s^2)*(5s)^2 + H  

H = 122.5 m

now knowing H, we can divide it by the height of a floor in the building and get the number of the floor.

N = 122.5m/2.88m = 42.5

this means that the apple was dropped in the floor 42 (the 0.5 means that the apple was not right where the floor 42 starts, it was dropped around the middle of the floor 42)

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63.4^{\circ}

Explanation:

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where I_0 is the intensity of the initial unpolarized light, while I_1 is the intensity of the polarized light coming out from the first filter. Light that comes out from the first polarizer is also polarized, in the same direction as the axis of the first polarizer.

When the (now polarized) light hits the second polarizer, whose axis of polarization is rotated by an angle \theta with respect to the first one, the intensity of the light coming out is

I_2 = I_1 cos^2 \theta (2)

If we combine (1) and (2) together,

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We want the final intensity to be 1/10 the initial intensity, so

I_2 = \frac{1}{10}I_0

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