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kompoz [17]
3 years ago
11

A car has a mass of 1.20 × 103 kilograms and a momentum of 2.00 × 104 kilogram meters/second. What is the velocity of the car?

Physics
2 answers:
patriot [66]3 years ago
8 0
<span>momentem = mass * velocity also, be sure to use the carrot for exponents 10^3 and 10^4. 20000/1200 = 16.7,This is your answer,That was hard lol.



Hope the helps.

</span>
Vera_Pavlovna [14]3 years ago
3 0
We know, Momentum = Mass * velocity 
2 * 10⁴ = (1.20 * 10³) (v)
v = 2 * 10⁴ / 1.20 * 10³
v = 1.67 * 10
v = 16.7 m/s

In short, Your Answer would be Option C

Hope this helps!
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A(n) 30 kg boy rides a roller coaster. The acceleration of gravity is 9.8 m/s 2 . With what force does he press against the seat
forsale [732]

Answer:

Force, F = 187.42 N

Explanation:

It is given that,

Mass of boy, m = 30 kg

Acceleration due to gravity, a=9.8\ m/s^2

Radius of curvature of the roller coaster, r = 15 m

Speed of the car, v = 7.3 m/s

The force acting on the boy are force of gravity and the centripetal force. The net force acting on him is as follows :

F=mg-\dfrac{mv^2}{r}

F=m(g-\dfrac{v^2}{r})

F=30\times (9.8-\dfrac{(7.3)^2}{15})

F = 187.42 N

So, he press against the seat with a force is 187.42 N. Hence, this is the required solution.

5 0
3 years ago
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otez555 [7]

1) 4°C : It has the highest density as shown on the graph.

2) Water expands when it freezes, making it less dense than just water.

3) The ice would sink to the bottom, then the rest of the water would freeze as well, the entire lake/river/whatever will freeze eliminating the organisms that live there.

7 0
3 years ago
Suppose that you are headed toward a plateau 55 meters high. If the angle of elevation to the top of the plateau is 40degrees​,
Iteru [2.4K]

Answer:

x=65.55m

Explanation:

Let x be the distance to the shore

From trigonometry properties:

tan(40^{o} )=\frac{55m}{x} \\x=\frac{55m}{tan(40^{o} )} \\x=65.55m

3 0
3 years ago
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joja [24]

Answer:17.44A

Explanation: Current density=I/Area

Area is given by 2.79mm^2=2.79×10^-6m^2

Current=I=current density ×Area=6.25×10^6 ×2.79×10^-6=17.44A

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3 years ago
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Ulleksa [173]
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