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Dmitry_Shevchenko [17]

3 years ago

5

A(n) 30 kg boy rides a roller coaster. The acceleration of gravity is 9.8 m/s 2 . With what force does he press against the seat

when the car moving at 7.3 m/s goes over a crest whose radius of curvature is 15 m? Answer in units of N.

1 answer:

forsale [732]3 years ago

5 0

Answer:

Force, F = 187.42 N

Explanation:

It is given that,

Mass of boy, m = 30 kg

Acceleration due to gravity, $a=9.8\ m/s^2$

Radius of curvature of the roller coaster, r = 15 m

Speed of the car, v = 7.3 m/s

The force acting on the boy are force of gravity and the centripetal force. The net force acting on him is as follows :

$F=mg-\dfrac{mv^2}{r}$

$F=m(g-\dfrac{v^2}{r})$

$F=30\times (9.8-\dfrac{(7.3)^2}{15})$

F = 187.42 N

So, he press against the seat with a force is 187.42 N. Hence, this is the required solution.

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tankabanditka [31]

Answer:

$80 m/s^2$

Explanation:

The acceleration of an object is given by:

$a=\frac{v-u}{t}$

where

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For the rocket in this problem,

u = 20,000 m/s

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Substituting,

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3 years ago

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NARA [144]

Answer:

171.5 N

Explanation:

The gravitational force on an object due to the Earth is given by

$F=mg$

where

m is the mass of the object

g is the acceleration due to gravity

The acceleration due to gravity at a certain height h above the Earth is given by

$g=\frac{GM}{(R+h)^2}$

where:

G is the gravitational constant

$M=5.98\cdot 10^{24} kg$ is the Earth's mass

$R=6.37\cdot 10^6 m$ is the Earth's radius

Here,

$h=6.38\cdot 10^6 m$

So the acceleration due to gravity is

$g=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})}{(6.37\cdot 10^6 + 6.38\cdot 10^6)^2}=2.45 m/s^2$

We know that the mass of the object is

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3 years ago

Describe an example where materials are prepared as fluids so that they can be moved easily

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Answer:

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Explanation:

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A truck is carrying a steel beam of length 13.0 m on a freeway. An accident causes the beam to be dumped off the truck and slide

PIT_PIT [208]

Answer:

$emf= 9.88 \times 10^{-3} T$

Explanation:

Given:

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speed of the beam, $v=20\,m.s^{-1}$

magnitude of the vertical magnetic field, $B=38\times 10^{-6} T$

According to the Faraday's law the emf induced in a rod passing transversely through a magnetic field is given as:

$emf= l.v.B$

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4 0

3 years ago

Help please:A boy weighing 30 kg rides a scooter. The total kinetic energy of the boy and the scooter is 437.6 J. Determine the

Ksenya-84 [330]

Answer:

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Explanation:

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5 0

3 years ago

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