A car moves with a speed of 72 km/h for 15 minutes and then with a speed of 80 km/h for the next 12 minutes. The total distance
2 answers:
Answer:
The total distance covered by the car is 3,810.08 m
Explanation:
Given;
initial speed of the car, u = 72 km/hr = 20 m/s
initial time, t₁ = 15 minutes = 900 s
final speed of the car, v = 80 km/hr = 22.22 m/s
final time, t₂ = 12 minutes = 720 s
The acceleration of the car is given as;
The total distance covered by the car is given as;
v² = u² + 2as
where;
s is the total distance covered by the car
22.22² = 20² + 2(0.0123)s
22.22² - 20² = 2(0.0123)s
93.728 = 0.0246s
s = 93.728 / 0.0246
s = 3,810.08 m
Therefore, the total distance covered by the car is 3,810.08 m
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Answer:
Explanation:
<u>Given:</u>
- Diameter of the plates of the capacitor, D = 21 cm = 0.21 m.
- Distance of separation between the plates, d = 1.0 cm = 0.01 m.
- Minimum value of electric field that produces spark,
When the dimensions of the plate of the capacitor is comparatively much larger than the distance of separation between the plates, then, according to the Gauss' law of electrostatics, the value of the electric field strength in the region between the plates of the capacitor is given by
where,
= surface charge density of the plate of the capacitor =
.
= magnitude of the charge on each of the plate.
= surface area of each of the plate =
= electrical permittivity of free space, having value =
For the minimum value of electric field that produces spark,
It is the maximum value of the magnitude of charge which can be added up to each of the plates of the capacitor.
Answer:
(1) passed through the foil
Explanation:
Ernest Rutherford conducted an experiment using an alpha particle emitter projected towards a gold foil and the gold foil was surrounded by a fluorescent screen which glows upon being struck by an alpha particle.
- When the experiment was conducted he found that most of the alpha particles went away without any deflection (due to the empty space) glowing the fluorescent screen right at the point of from where they were emitted.
- While a few were deflected at reflex angle because they were directed towards the center of the nucleus having the net effective charge as positive.
- And some were acutely deflected due to the field effect of the positive charge of the proton inside the nucleus. All these conclusions were made based upon the spot of glow on the fluorescent screen.
