A car moves with a speed of 72 km/h for 15 minutes and then with a speed of 80 km/h for the next 12 minutes. The total distance
2 answers:
Answer:
The total distance covered by the car is 3,810.08 m
Explanation:
Given;
initial speed of the car, u = 72 km/hr = 20 m/s
initial time, t₁ = 15 minutes = 900 s
final speed of the car, v = 80 km/hr = 22.22 m/s
final time, t₂ = 12 minutes = 720 s
The acceleration of the car is given as;
The total distance covered by the car is given as;
v² = u² + 2as
where;
s is the total distance covered by the car
22.22² = 20² + 2(0.0123)s
22.22² - 20² = 2(0.0123)s
93.728 = 0.0246s
s = 93.728 / 0.0246
s = 3,810.08 m
Therefore, the total distance covered by the car is 3,810.08 m
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Answer:
The acceleration of the train is 5 m/s².
Explanation:
Given:
let the initial velocity of a train = 5 m/s and
final velocity of a train = 45 m/s
time taken = 8 s
To find:
acceleration: ?
Solution:
We define acceleration as change in velocity per unit time that is the difference between the final velocity and initial velocity divided by time.
On substituting the above values we get the required acceleration
Therefore,the acceleration of the train is 5 m/s².