Based on the data provided;
- number of moles of helium gas is 1.25 moles
- pressure at peak temperature is 259.3 kPa
- internal pressure is above 256 kPa, therefore, the balloon will burst.
- pressure should be reduced to a value less than 256 kPa by reducing the temperature
<h3>What is the ideal has equation?</h3>
The ideal gas equation relatesthe pressure, volume, moles and temperature of a gas.
The moles of helium gas is calculated using the Ideal gas equation:
n is the number of moles of gas
R is molar gas constant = 8.314 L⋅kPa/Kmol
P is pressure = 239 kPa
T is temperature = 21°C = 294 K
V is volume = 12.8 L
Therefore;
n = PV/RT
n = 239 × 12.8 / 8.314 × 294
n = 1.25 moles
The number of moles of helium gas is 1.25 moles
At peak temperature, T = 46°C = 319 K
Using P1/T1 = P2/T2
P2 = P1T2/T1
P2 = 239 × 319/294
P2 = 259.3 kPa
The pressure at peak temperature is 259.3 kPa
At 42°C, T = 315 K
Using P1/T1 = P2/T2
P2 = P1T2/T1
P2 = 239 × 315/294
P2 = 256.07 kPa
Since the internal pressure is above 256 kPa, the balloon will burst.
The pressure should be reduced to a value less than 256 kPa by reducing the temperature.
Learn more about gas ideal gas equation at: brainly.com/question/12873752
It can be in either state.....
Answer:

Explanation:
SO in order to calculate the specific latent heat of fusion, you need to remember the formula:

Where
representes the specific latent heart of fusion.
represents the heat energy added, usually represented in kJ
represents the mass of the object, in kg.
Now that we have our formula we just have to put our values into the formula:



SO our answer would be 
Answer: Option (c) is the correct answer.
Explanation:
It is known that when we tend to dilute an impure product with too much of solvent then it will lead to dissolution of the solute. As a result, the chances of formation of crystal reduces.
And, when we increase the temperature then there will occur increase in the number of collisions between the solute and solvent molecules.
Hence, solubility of the solute also increases with increase in temperature, placing it on ice bath will further reduce the crystal formation, hence no crystal should be formed in the reaction.
Thus, we can conclude that the result of crystals boiling the impure product with too much solvent and then cooling on ice is that no crystals are produced.