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Kazeer [188]
3 years ago
9

Two groups were tasked to measure the mass of the metal objects given by their teacher. Rachel’s group has the following data fo

r 3 trials: 97 g, 98 g, and 99 g. Meanwhile, Ashley’s group has 99.5 g, 100.1 g, and 100.5 g. If the accepted value for the metal’s mass is 100 g, how will you describe the data of each group in terms of precision and accuracy?
Chemistry
1 answer:
Studentka2010 [4]3 years ago
5 0

The measurement of Rachel’s group is precise but not accurate while the measurement of Ashley’s group is accurate but not precise.

Precision has to do with how close together the values obtained from a scientific measurement is. If we take a look at the values obtained by  Rachel’s group, we will notice that the values are exactly 1.00 g apart. This means that the values are precise.

However, these values a far from the actual value which is 100.00 g therefore the measurement of Rachel’s group is precise but not accurate.

On the other hand, the values obtained by Ashley’s group are; 99.5 g, 100.1 g, and 100.5 g. These values are very close to the actual value which is 100.00 g  hence they are accurate.

The values obtained by Ashley’s group do not have consistent intervals therefore, they are not precise.

Learn more; brainly.com/question/15664210

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<u>Answer:</u> The value of K_{eq} is 0.044

<u>Explanation:</u>

We are given:

Initial moles of methane = 4.10\times 10^{-2}mol=0.0410moles

Initial moles of carbon tetrachloride = 6.51\times 10^{-2}mol=0.0651moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}

So, concentration of methane = \frac{0.0410}{1.00}=0.0410M

Concentration of carbon tetrachloride = \frac{0.0651}{1.00}=0.0651M

The given chemical equation follows:

                    CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)

<u>Initial:</u>          0.0410    0.0651

<u>At eqllm:</u>     0.0410-x   0.0651-x       2x

We are given:

Equilibrium concentration of carbon tetrachloride = 6.02\times 10^{-2}M=0.0602M

Evaluating the value of 'x', we get:

\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M

Now, equilibrium concentration of methane = 0.0410-x=[0.0410-0.0049]=0.0361M

Equilibrium concentration of CH_2Cl_2=2x=[2\times 0.0049]=0.0098M

The expression of K_{eq} for the above reaction follows:

K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}

Putting values in above expression, we get:

K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044

Hence, the value of K_{eq} is 0.044

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Answer:

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