Give me some answer choices and i will be happy to help
The horizontal component of the plane's velocity is 85.96 mph and the vertical component of the plane's velocity is 487.5 mph.
<h3>
Component form of the velocity of the airplane</h3>
The component form of the velocity of the airplane includes both horizontal and vertical velocity and it is calculated as follows;
Vx = V cosθ
Vy = V sinθ
where;
- Vx is horizontal component of the velocity
- Vy is vertical component of the velocity
- θ is the angle of the velocity measured with respect to horizontal axis
θ = 170 - 90 = 80⁰
<h3>Horizontal component of the velocity</h3>
Vx = 495 mph (cos 80)
Vx = 85.96 mph
<h3>Vertical component of the velocity</h3>
Vy = 495 mph (sin 80)
Vy = 487.5 mph
Thus, the horizontal component of the plane's velocity is 85.96 mph and the vertical component of the plane's velocity is 487.5 mph.
Learn more about components of velocity here: brainly.com/question/24949996
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Answer:
m=417.24 kg
Explanation:
Given Data
Initial mass of rocket M = 3600 Kg
Initial velocity of rocket vi = 2900 m/s
velocity of gas vg = 4300 m/s
Θ = 11° angle in degrees
To find
m = mass of gas
Solution
Let m = mass of gas
first to find Initial speed with angle given
So
Vi=vi×tanΘ...............tan angle
Vi= 2900m/s × tan (11°)
Vi=563.7 m/s
Now to find mass
m = (M ×vi ×tanΘ)/( vg + vi tanΘ)
put the values as we have already solve vi ×tanΘ
m = (3600 kg ×563.7m/s)/(4300 m/s + 563.7 m/s)
m=417.24 kg
Answer:
Explanation:
The capacitance of the electrode is given by:
where
C is the capacitance
Q is the charge on the electrode
V is the potential difference
In this problem, we have
V = 9.0 V
Substituting into the equation, we find
(5 nF)
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