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attashe74 [19]
3 years ago
9

How is nitrogen converted in the nitrogen cycle

Chemistry
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

nitrogen fixing bacteria

Explanation:

These bacteria made the nitrogen suitable for plant use.

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Hi:) why covalent substances don’t have free moving ions / electrons?
Igoryamba

Answer:

Covalent compounds don't contain ions because they make bonds by sharing electrons. In addition, they don't have any charge carries that are free to move so they can't carry electric current

Explanation:

6 0
3 years ago
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HELP ASAP!!!!
Vinvika [58]

Answer: A, C, D

Explanation:

Right on Edge

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3 years ago
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A 250.0 mL sample of aqueous solution contains an unknown amount of dissolved NaBr. Excess aqueous Pb(NO3)2is then added to this
Scrat [10]

Answer:

A. 0.0655 mol/L.

B. PbBr2.

C. Pb2+(aq) + Br- --> PbBr2(s).

Explanation:

Balanced equation of the reaction:

Pb(NO3)2(aq) + 2NaBr(aq) --> PbBr2(s) + 2NaNO3(aq)

A.

Number of moles

PbBr2

Molar mass = 207 + (80*2)

= 367 g/mol.

Moles = mass/molar mass

= 3.006/367

= 0.00819 mol.

Since 2 moles of NaBr reacted to form 1 mole of PbBr2. Therefore, moles of NaBr = 2*0.00819

= 0.01638 moles of NaBr.

Since, the ionic equation is

NaBr(aq) --> Na+(aq) + Br-(aq)

Since 1 moles of NaBr dissociation in solution to give 1 mole of Br-

Therefore, molar concentration of Br-

= 0.0164/0.25 L

= 0.0655 mol/L.

B.

PbBr2

C.

Pb(NO3)2(aq)--> Pb2+(aq) + 2No3^2-(aq)

2NaBr(aq) --> 2Na+(aq) + 2Br-(aq)

Net ionic equation:

Pb2+(aq) + 2Br- --> PbBr2(s)

8 0
3 years ago
A sample consisting of n mol of an ideal gas undergoes a reversible isobaric expansion from volume Vi to volume 3Vi. Find the ch
kolezko [41]

Answer:

The change in entropy of gas is \Delta S= nC_{P}ln3

Explanation:

n= Number of moles of gas

Change in entropy of gas = ds= \int \frac{dQ}{T}

dQ= nC_{p}dT

From the given,

V_{i}=V

V_{f}=3V

Let "T" be the initial temperature.

\frac {V_{i}}{T_{i}}=\frac {V_{f}}{T_{f}}

\frac {V}{T}=\frac {3V}{T_{f}}

{T_{f}} = 3T

\int ds = \int ^{T_{f}}_{T_{i}} \frac{nC_{P}dT}{T}

\Delta S = nC_{p}ln(\frac{T_{f}}{T_{i}})

\Delta S = nC_{p}ln3

Therefore, The change in entropy of gas is \Delta S= nC_{P}ln3

3 0
3 years ago
What is the element that lies in group no 29?​
Amiraneli [1.4K]
Ahh there isn’t a group 29 on the periodic table, but do you mean which element had the atomic number 29 because that would be Copper (Cu).

Hope this helps :)
4 0
3 years ago
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