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3 years ago

Briefly explain why there is a constant temperature plateau in the cooling curve

1 answer:

4 0

This plateau is where a phase change occurs. Likely, this cooling curve observes the changing of a liquid into a solid (so that the temperature is quantifiable). As something cools, it’s losing energy to the surroundings; when a phase change occurs, like liquid to solid, energy isn’t lost directly from the atom, but instead the energy maintained by free motion of the atom is used. This lack of motion reduces it into a lattice (all while maintaining a constant internal energy), finalizing the phase change, after which energy is lost directly from the atom again.

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What is the product of the reaction between HCIO3 and KOH

NISA [10]

Answer:

The products are: KCl03 and H20.

Explanation:

The reaction between HC03 (chloric acid) and KOH (potassium hydroxide) is:

HC03 + KOH ----> KCl03 (KCl03 and H20) + H20 (water)

<em>The reaction is of the double displacement type (in this case parts of the reagents are exchanged, producing two generating new compounds).</em>

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3 years ago

Which of the following is NOT true about a C-14 atom?

romanna [79]

Answer:

option C. it contain 6 neutrons.

Explanation:

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3 years ago

The amount of heat energy needed to heat 200 g of water from 15 °C to its boiling point, and boil it, is

Svetllana [295]

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3 years ago

Determine balanced chemical equations for the following chemical reactions

Lena [83]

Answer:

hey just where are the rections keep a pic

Explanation:

okay?.........................................

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3 years ago

Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin

STALIN [3.7K]

Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of $KI$ and $AgNO_3$ .

$\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}$

Molar mass of KI = 166 g/mole

$\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole$

and,

$\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole$

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

$KI+AgNO_3\rightarrow KNO_3+AgI$

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of $AgNO_3$

So, 0.0178 mole of KI react with 0.0178 mole of $AgNO_3$

From this we conclude that, $AgNO_3$ is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $AgI$