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harina [27]
3 years ago
12

An elevator ascends at a constant speed of 4 m/s. How much time is required for the elevator in order to travel 200m upwards?

Physics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

Explanation:

Hope this helps, cheers

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A body of mass 500kg moving at a speed of 10m/s reaches the speed of 50m/s in 20s.The force exerted is
Leona [35]

Answer:

answer is 1000 N

formula used-

<em><u>F= m x (v-u/t)</u></em>

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6 0
3 years ago
A river has a steady speed 0.500 m/s. A student swims upstream a distance of1.00 km and swims back to the starting point. a) If
Ivahew [28]

Answer:

a) 33.6 min

b) 13.9 min

c)  Intuitively, it takes longer to complete the trip when there is current because, the swimmer spends much more time swimming at the net low speed (0.7 m/s) than the time he spends swimming at higher net speed (1.7 m/s).


Explanation:


The problem deals with relative velocities.

  • Call Vr the speed of the river, which is equal to 0.500 m/s
  • Call Vs the speed of the student in still water, which is equal to 1.20 m/s
  • You know that when the student swims upstream, Vr and Vs are opposed and the net speed will be Vs - Vr
  • And when the student swims downstream, Vr adds to Vs and the net speed will be Vs + Vr.

Now, you can state the equations for each section:

  • distance = speed × time
  • upstream: distance = (Vs - Vr) × t₁ = 1,000 m
  • downstream: distance = (Vs + Vr) × t₂ = 1,000 m

Part a). To state the time, you substitute the known values of Vr and Vs and clear for the time in each equation:

  • (Vs - Vr) × t₁ = 1,000 m
  • (1.20 m/s - 0.500 m/s) t₁ = 1,000 m⇒ t₁ = 1,000 m / 0.70 m/s ≈ 1429 s
  • (1.20 m/s + 0.500 m/s) t₂ = 1,000 m ⇒ t₂ = 1,000 m / 1.7 m/s ≈ 588 s
  • total time = t₁ + t₂ = 1429s + 588s =  2,017s
  • Convert to minutes: 2,0147 s ₓ 1 min / 60s ≈ 33.6 min

Part b) In this part you assume that the complete trip is made at the velocity Vs = 1.20 m/s


  • time = distance / speed = 1,000 m / 1.20 m/s ≈ 833 s ≈ 13.9 min

Part c) Intuitively, it takes longer to complete the trip when there is current because the swimmer spends more time swimming at the net speed of 0.7 m/s than the time than he spends swimming at the net speed of 1.7 m/s.

6 0
4 years ago
1. Any push or pull is called
timama [110]

Answer:

b  ok

Explanation:

7 0
3 years ago
It has been suggested that a heat engine could be developed that made use of the fact that the temperature several hundred meter
lesantik [10]

Answer:

efficiency = 5.4%

Explanation:

Efficiency of heat engine is given as

\eta = \frac{W}{Q_{in}}

now we will have

W = Q_1 - Q_2

so we will have

\eta = 1 - \frac{Q_2}{Q_1}

now we know that

\frac{Q_2}{Q_1} = \frac{T_2}{T_1}

so we have

\eta = 1 - \frac{T_2}{T_1}

\eta = 1 - \frac{273+6}{273+22}

\eta = 0.054

so efficiency is 5.4%

8 0
3 years ago
3 kg of wet clothes are hung on the middle of a clothesline with posts 6 ft apart. The clothesline sags down by 3 feet. What is
miskamm [114]

Answer:

Tension in string equals 14.715 Newtons

Explanation:

The situation is represented in the figure attached below:

For equilibrium of the clothes along y- axis we have

\sum F_{v}=0\\\\\Rightarrow 2Tcos(\theta )=W\\\\\therefore T=\frac{W}{2cos(\theta )}

Applying values we get

\sum F_{v}=0\\\\\Rightarrow 2Tcos(\theta )=W\\\\\therefore T=\frac{3\times 9.81}{2\times 1}=14.715N(\because cos(\theta )=\frac{3}{3}=1)

4 0
3 years ago
Read 2 more answers
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