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Tems11 [23]
3 years ago
12

Which has more momentum, a small object moving 10 miles per hours or a large object at rest?

Physics
1 answer:
xeze [42]3 years ago
3 0
Well the object will have no Momentum since it is not moving, so a small object that is going 10 mph will have Momentum.
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What is the purpose of the thermal energy tranfer lab
iren2701 [21]

Answer:thermal Energy Transfer in Mixtures Purpose: The purpose of this experiment is to discover how exactly the final temperature of a mixture, involving a substance and hot water, is affected and impacted by the type of substance used. This means that when hot water is mixed with another substance, it must be determined

Explanation:

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6 0
2 years ago
The natural enzyme reaction in food slowly breaks it down and eventually causes it to spoil. what 2 things halt this enzyme reac
ollegr [7]

Answer: the answer is storing properly in refrigeration.

Explanation:

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2 years ago
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A 5 cm spring is suspended with a mass of 3.8589 g attached to it which extends the spring by 1.5747 cm. The same spring is plac
lana66690 [7]

Answer:

charges of the beads is 1.173 ×10^{-15} C

Explanation:

given data

mass = 3.8589 g = 0.003859 kg

spring length = 5 cm = 0.05 m

extend spring x = 1.5747 cm = 0.15747 m

spring's extension = 0.0116 m

to find out

charges of the beads

solution

we know that force is

force = mass × g

force = 0.003859 × 9.8

force = 0.03782 N

so we know  force for mass

force  = -kx

so k = force / x

put here force and x value

k = -0.03782 / 0.1575

k = -0.24 N/m

and

force for spring's extension

force = -kx

force = -0.24 ( 0.0116) = 0.002784 N

so here

total length L = 0.05 + 0.0116 = 0.0616

so charges of the beads = force × L² / ke

charges of the beads = 0.002784 × (0.0616)² / (9 ×10^{9} )

so charges of the beads = 1.173 ×10^{-15} C

3 0
3 years ago
A child is sliding down a slide at the playgound. is mechanicalenergy conserved
Flauer [41]

No. Mechanical energy is not conserved.  There's quite a bit of friction on the slide.  So some of the potential energy is lost to heat on the way down, and the child arrives at the bottom with hot pants and less kinetic energy than you might expect.

5 0
3 years ago
While running at a constant velocity, how should you throw a ball with respect to you so that you can catch it yourself?
timurjin [86]
You are running at constant velocity in the x direction, and based on the 2D definition of projectile motion, Vx=Vxo. In other words, your velocity in the x direction is equal to the starting velocity in the x direction. Let's say the total distance in the x direction that you run to catch your own ball is D (assuming you have actual values for Vx and D). You can then use the range equation, D= (2VoxVoy)/g, to find the initial y velocity, Voy. g is gravitational acceleration, -9.8m/s^2. Now you know how far to run (D), where you will catch the ball (xo+D), and the initial x and y velocities you should be throwing the ball at, but to find the initial velocity vector itself (x and y are only the components), you use the pythagorean theorem to solve for the hypotenuse. Because you know all three sides of the triangle, you can also solve for the angle you should throw the ball at, as that is simply arctan(y/x). 
5 0
3 years ago
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