Answer:
The electric field is 16666.66 V/m.
The surface charge density is 
The capacitance is 
The charge on each plate is 
Explanation:
Given that,
Area =7.70 cm²
Distance = 1.50 mm
Potential difference = 25.0 V
Suppose we find the electric field between the plates, the surface charge density, the capacitance and the charge on each plates.
We need to calculate the electric field
Using formula of electric field

Put the value into the formula


We need to calculate the charge density
Using formula of charge density

Put the value into the formula


We need to calculate the capacitance
Using formula of capacitance

Put the value into the formula


We need to calculate the charge
Using formula of charge

Put the value into the formula


Hence, The electric field is 16666.66 V/m.
The surface charge density is 
The capacitance is 
The charge on each plate is 