The fuel released 90 calories of heat.
Let suppose that water experiments an entirely <em>sensible</em> heating. Hence, the heat released by the fuel is equal to the heat <em>absorbed</em> by the water because of principle of energy conservation. The heat <em>released</em> by the fuel is expressed by the following formula:
(1)
Where:
- Mass of the sample, in grams.
- Specific heat of water, in calories per gram-degree Celsius.
- Temperature change, in degrees Celsius.
If we know that
,
and
, then the heat released by the fuel is:
![Q = (10\,g)\cdot \left(1\,\frac{cal}{g\cdot ^{\circ}C} \right)\cdot (9\,^{\circ}C)](https://tex.z-dn.net/?f=Q%20%3D%20%2810%5C%2Cg%29%5Ccdot%20%5Cleft%281%5C%2C%5Cfrac%7Bcal%7D%7Bg%5Ccdot%20%5E%7B%5Ccirc%7DC%7D%20%5Cright%29%5Ccdot%20%289%5C%2C%5E%7B%5Ccirc%7DC%29)
The fuel released 90 calories of heat.
We kindly invite to check this question on sensible heat: brainly.com/question/11325154
The correct answer is A.
B is incorrect because that only applies to nuclear fission.
C is incorrect because it only applies to nuclear fusion.
D is incorrect because energy can be neither created nor destroyed meaning that this statement is physically impossible,
Answer:
A. 2C + H₂ ⟶ CH₄
Explanation:
A. 2C + H₂ ⟶ CH₄
UNBALANCED. 2C on the left and 1C on the right
B. 2Al₂O₃ ⟶ 4Al + 3O₂
Balanced. Same number of each type of atom on each side.
C. 2H₂O₂ ⟶ 2H₂O + O₂
Balanced. Same number of each type of atom on each side.
D. 2C₂H₆ + 7O₂ ⟶ 4CO₂ + 6H₂O
Balanced. Same number of each type of atom on each side.
Answer:
alkali metals- Group 1
Explanation:
they have less valence electrons and therefore are more reactive