Answer:
1.33 × 10⁻³¹ m
Gamma rays
Explanation:
1 mol of photons required for the photoionization of N₂ has an energy (E) of 1495 kJ = 1495 × 10³ J = 1.495 × 10⁶ J. We can find the wavelength (λ) associated with this energy using the Planck-Einstein equation.
E = h . c . λ⁻¹
where,
h is the Planck's constant
c is the speed of light
E = h . c . λ⁻¹
λ = h . c . E⁻¹ = (6.63 × 10⁻³⁴ J.s) . (3.00 × 10⁸ m/s) . (1.495 × 10⁶ J)⁻¹ = 1.33 × 10⁻³¹ m
This wavelength corresponds to the Gamma rays region of the spectrum.
The answer is Cartography.
Answer:
C6H12O6.
Explanation:
Adding up the relative atomic masses of the elements
C + 2H + O
= 12 + 2*1 + 16.
= 30.
180 / 30 = 6 so the molecular formula is:
C6H12O6.
