3 years ago

What is the distance between (5,3) and (-2,2) in simpilist radical form

Mathematics

1 answer:

Mariulka [41]3 years ago

3 0

Answer:

$distance \: btween \:$

(5,3) and (-2,2)

$\sqrt{ {(5 - ( - 2)) }^{2} + {(3 - 2)}^{2} } \\ \\ = \sqrt{ {(5 + 2)}^{2} + {1}^{2} } \\ \\ = \sqrt{ {7}^{2} + 1} \\ \\ = \sqrt{49 + 1 } = \sqrt{50} = 5 \sqrt{2}$

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Solve The Triangle (See Picture!!)

joja [24]

Answer:

Step-by-step explanation:

use sin formula

$\frac{a}{sin \alpha } =\frac{b}{sin \beta } =\frac{c}{sin \gamma} \\\frac{10}{sin~40} =\frac{12}{sin ~\beta } \\sin~\beta =\frac{12}{10} \times sin~40\\ \beta=sin^{-1}(1.2 sin ~40)\approx 50.5 ^\circ\\\gamma=180-(40+50.5)=89.5^\circ\\\frac{c}{sin~89.5}=\frac{10}{sin~40} \\c=\frac{sin~89.5}{sin ~40} \times 10 \approx 15.6\\D$