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3 years ago

What is the distance between (5,3) and (-2,2) in simpilist radical form

Mathematics

1 answer:

Mariulka [41]3 years ago

3 0

Answer:

$distance \: btween \:$

(5,3) and (-2,2)

$\sqrt{ {(5 - ( - 2)) }^{2} + {(3 - 2)}^{2} } \\ \\ = \sqrt{ {(5 + 2)}^{2} + {1}^{2} } \\ \\ = \sqrt{ {7}^{2} + 1} \\ \\ = \sqrt{49 + 1 } = \sqrt{50} = 5 \sqrt{2}$

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3 years ago

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Aloiza [94]

Answer:

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3 years ago

Can u please help me with this math assignment

Troyanec [42]

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3 years ago

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28%

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Let x = the original price

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3 years ago

What is the measure of WUX in Circle V ?

Alja [10]

Answer:

$arc\ WUX=120^o$

Step-by-step explanation:

<u><em>The complete question is:</em></u>

In circle V, angle WXZ measures 30°. Line segments WV, XV, ZV, and YV are radii of circle V. Circle V is shown. Line segments W V, X V, Z V, and Y V are radii. Lines are drawn from point W to point X and from point Z to point Y to form secants. Point U is on the circle between points W and X. What is the measure of Arc W U X in circle V?

The picture of the question in the attached figure

step 1

Find the measure of angle XWV

we know that

The triangle VWX is an isosceles triangle, because has two equal sides (VX=VW)

we have

$m\angle WXZ=30^o\\m\angle WXV=m\angle WXZ$