Please help ASAP!!!!!!!!!!

How do you round 23 to the nearest thousand?

Zielflug [23.3K]

You cannot round 23 to the nearest thousand.

There are only TWO PLACE VALUES in 23: ones and tens.

6 0

3 years ago

How many ways are

jekas [21]

This link is a trap so sex traffickers can track you then kidnap you. there’s been an influx of these “answers” on this app. if you see them report them immediately. they’re praying on children and it’s so dangerous.

3 0

2 years ago

If a central angle measures 25, then the measure of its intercepted arc is

borishaifa [10]

Medida do angulo central = medida do arco interceptado
arco = 25º e ângulo central = 25º

7 0

3 years ago

If you are 600 m from a batter when you see him hit a ball, how long will you wait to hear the sound of the bat hitting the ball

Molodets [167]

Answer:

The speed of sound at 20°C is 343.42 m/s.

You have to wait 1.75 seconds to hear the sound of the bat hitting the ball

Step-by-step explanation:

Speed of Sound

The speed of sound is not constant with temperature. Generally speaking, the greater the temperature, the greater the speed of sound.

The approximate speed of sound in dry air at temperatures T near 0°C is calculated from:

$\displaystyle v_{\mathrm {s} }=(331.3+0.606\cdot T )~~~\mathrm {m/s}$

The air is at T=20°C, thus the speed of sound is:

$\displaystyle v_{\mathrm {s} }=(331.3+0.606\cdot 20 )~~~\mathrm {m/s}$

$v_{\mathrm {s} }=343.42\ m/s$

The speed of sound at 20°C is 343.42 m/s.

To calculate the time to hear the sound after the batter hits the ball, we use the formula of constant speed motion:

$\displaystyle v=\frac{d}{t}$

Where d is the distance and t is the time. Solving for t:

$\displaystyle t=\frac{d}{v}$

Substituting the values v=343.42 m/s and d=600 m:

$\displaystyle t=\frac{600}{343.42}$

t = 1.75 s

You have to wait 1.75 seconds to hear the sound of the bat hitting the ball

6 0

3 years ago

A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute q in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute h in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for d, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for d in the second equation to find h, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for d and 16 for h in the third equation to find q, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

6 0

3 years ago