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3 years ago

Graph the system of equations. Identify the type of system as consistent, Inconsistent, or equivalent.

Mathematics

2 answers:

Alisiya [41]3 years ago

6 0

Answer:

Step-by-step explanation:

natita [175]3 years ago

5 0

Should=12 because it added

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4x – 8<br><br> Please helppp

Nadya [2.5K]

-2

Divide each term (-4x = 8 by -4)

Cancel the common factor of -4

x = 8/-4

THEN DIVIDE

x=-2

4 0

2 years ago

What is the solution to the system of equations y = -x - 5 and y = 2x + 4

Delvig [45]

Answer:

(-3,-2)

Step-by-step explanation:

y = -x - 5

y = 2x + 4

plug in one of the y equations

(2x+4)= -x - 5

2x+4=-x-5

3x=-9

x= -3

plug in x to one of the y equations

y= -(-3) -5

y=3-5

y= -2

x= -3, y= -2

4 0

3 years ago

A new car is purchased for 22400 dollars. The value of the car depreciates at 11% per year. To the nearest tenth of a year , how

m_a_m_a [10]

Answer:

t= 12.9 years

Step-by-step explanation:

Value after t years = initial value ( 1 - r )^t

Where,

Value after t years= $5000

Initial value = $22,400

r= depreciation rate = 11%

t= length of time (years)

Value after t years = initial value ( 1 - r )^t

5000 = 22,400 ( 1 - 0.11)^t

5000 = 22,400(0.89)^t

Divide both sides by 22,400

(0.89)^t = 5000 / 22,400

(0.89)^t = 0.2232

Take the log of both sides

t log 0.89 = log 0.2232

t= log 0.2232 / log 0.89

= -0.6513 / -0.0506

= 12.87

t= 12.9 years

5 0

3 years ago

The circular stream of water from a faucet is observed to taper from a diameter of 20 mm to 10 mm in a distance of 50 cm. Determ

steposvetlana [31]

Solution:

From Bernoulli equation

$\frac{1}{2}$ ρ $V_{1}^{2}$ + ρgh = $\frac{1}{2}$ ρ $V_{2}^{2}$ , where ρ is density of water, h – height difference and $V_{1}$ and $V_{2}$ are the velocities in upper and lower cross sections correspondingly. We take into account that the pressure in both cross-sections is the same and equal to the atmospheric one.

From the continuity and assuming water incompressible:

$\pi r_{1}^{2}$ $V_{1}$ = $\pi r_{2}^{2}$ $V_{2}$ , where $A_{1}$ and $A_{2}$ are the corresponding cross-sections. As the lower diameter is twice as low as the upper one, we can conclude that $V_{1} = \frac{V_{2}}{4}$