Question

A stunt pilot of mass 49.0 kg who has been diving her airplane vertically pulls out of the dive by changing her course to a circle in a vertical plane. Part A If the plane's speed at the lowest point of the circle is 94.0 m/s , what is the minimum radius of the circle for the acceleration at this point not to exceed 4.00g ?

Answer 1

Answer:

225.4 m

Explanation:

We are given that

Mass =m=49 kg

a.Speed,v=94 m/s

We have to find the minimum radius of the circle for the acceleration at this point not to exceed 4 g.

We know that

Radial acceleration,$a=\frac{v^2}{R}$

Using the formula

$4g=\frac{(94)^2}{R}$

$R=\frac{(94)^2}{4g}$

We know that g=$9.8m/s^2$

$R=\frac{(94)^2}{4\times 9.8}$

$R=225.4 m$