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hram777 [196]
3 years ago
9

Which are examples of contact forces?

Chemistry
1 answer:
lesantik [10]3 years ago
8 0

Answer:

Contact force is a force that requires a contact between two bodies and is ubiquitous in nature

Explanation:

The force is distributed in two categories i.e

  • Contact force
  • Non-Contact force

Contact Forces  are the forces which is requires a contact between two bodies to occur.

The Types of contact forces are given below:

  • Frictional Force
  • Tension Force
  • Normal Force
  • Air Resistance Force
  • Applied Force
  •  Spring Force

Some common daily examples of the contact force are

  1. Frictional force between the tyres of a moving vehicle and the road.
  2. Air flowing in opposite direction of a moving object.
  3. Pushing a table with hand and the friction between its base and floor.
  4. Stretching a rubber band with hands etc.

Also non-contact forces are Gravitational force, Electrical force and Magnetic force.

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For the reaction Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3 how many grams of calcium carbonate, CaCO3, are produced from 79.3 g of sodium car
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Answer:

74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.

Explanation:

The balanced reaction is:

Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • Ca(NO₃)₂: 1 mole
  • CaCO₃: 1 mole
  • NaNO₃: 2 mole

Being the molar mass of the compounds:

  • Na₂CO₃: 106 g/mole
  • Ca(NO₃)₂: 164 g/mole  
  • CaCO₃: 100 g/mole
  • NaNO₃: 85 g/mole

then by stoichiometry the following quantities of mass participate in the reaction:

  • Na₂CO₃: 1 mole* 106 g/mole= 106 g
  • Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
  • CaCO₃: 1 mole* 100 g/mole= 100 g
  • NaNO₃: 2 mole* 85 g/mole= 170 g

You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of  CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of  CaCO₃?

mass of CaCO_{3} =\frac{79.3 grams of Na_{2} CO_{3} *100 grams of of CaCO_{3}}{106 grams of Na_{2} CO_{3}}

mass of CaCO₃= 74.81 grams

<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>

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Volume of egg= 58.5-50.0 = 8.5 mL

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