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gayaneshka [121]

2 years ago

7

Three concentric circles have radii of lengths 2, 4, and 8 feet. What is the length of the shortest line segment that has at lea

st one point in common with each of the three circles?

1 answer:

Kisachek [45]2 years ago

5 0

The shortest distance between 2 concentric circles is the difference of their radii. Thus the answer is 8-2=6

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Adding and subtracting positive and negative numbers

algol13

Answer:

Step-by-step explanation:

Rule Example

+(+) Two like signs become a positive sign 3+(+2) = 3 + 2 = 5

−(−) 6−(−3) = 6 + 3 = 9

+(−) Two unlike signs become a negative sign 7+(−2) = 7 − 2 = 5

−(+) 8−(+2) = 8 − 2 = 6

5 0

2 years ago

Read 2 more answers

If you raise 4 to the 214th power, what is the units digit of the result

Len [333]

$\begin{array}{lrlll}
4^1&\boxed{4}\\
4^2&1\boxed{6}\\
4^3&6\boxed{4}\\
4^4&25\boxed{6}\\
4^5&102\boxed{4}\\
4^6&409\boxed{6}
\end{array}\impliedby \textit{see the pattern for 4?}$

notice, it goes 4,6 then 4, 6 again, and so on and so on
based on whatever exponent it may have

now, you're being asked, what 214 will give? 4 or 6?

4 0

3 years ago

Please help <br> (There's a picture)<br> #33 and #34

evablogger [386]

#33 is 0.3 times 42, because 0.3 is basically 30%, and you always multiply the percent by the number to get the answer. It could also be 3/10 times 42.

3 0

3 years ago

Shawna packs blocks at the ABC. Blocks factory. She packs thousands in crates and tens in stacks. How can she pack an order for

shusha [124]

She can do 12.5 stacks.

7 0

2 years ago

Read 2 more answers

Find 3 consecutive even num big ears where the product of the smaller two numbers is 52 less than the square of the largest numb

Ksju [112]

Answer:

Smallest consecutive number = 6

Second consecutive number = 8

Largest consecutive number = 10

Step-by-step explanation:

Let us assume the first even number = k

Then the next consecutive even number (k +2)

And the third consecutive even number = (k+2) + 2= k + 4

Now, Product of two smaller number = k (k+2)

Also, the square of the largest number = $(k+4)^2$

Now, according to the question:

$k(k+2) = (k+4)^2 - 52$

Now, using ALGEBRAIC IDENTITY: $(a+b)^2 = a^2 + b^2 + 2ab$

$k(k+2) = (k+4)^2 - 52 \implies k ^2 + 2k = k^2 + 8k + 16 -52\\or, 2k - 8k = 16 - 52 \implies -6k = -36\\\implies k = 36/6= 6$

or, k = 6

Hence, the smallest consecutive number = k = 6

Second consecutive number = k + 2 = 6 + 2 = 8

Largest consecutive number = k + 4 = 6 + 4 = 10

Hence, 6 , 8 and 10 are the required numbers.

7 0

2 years ago