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marusya05 [52]
3 years ago
7

Find the volume of the cone.

Mathematics
2 answers:
Contact [7]3 years ago
6 0

<em>V</em>≈301.59

I think this is the answer.

Hope this helps!

Fittoniya [83]3 years ago
3 0

The answer is 96pi units^3

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Hi who can help me do this 2quetion,I will mark brainlest ​
hodyreva [135]

Step-by-step explanation:

8.  log_{10}(2.15)   = 0.332 \: then \:   log_{10}(21500)   = ..... \\  log(21500)  =  log(2.15 \times 10000)  \\   =  log(2.15)  +  log(10000)  \\   = log_{10}(2.15)  +  log_{10}( {10}^{4} )  \\  = 0.332 + 4 log_{10}(10)  \\  = 0.332 + 4(1) \\  log_{10}(21500)  = 4.332

9. log(2)=a, log(3)=b, then log(36)=______

log(36) = log(6*6) = log(6) + log(6)

log(36)= log(6) + log(6)

log(36) = log(3*2) + log(3*2)

log(36) = (log(3) + log(2)) + (log(3) + log(2))

log(36) = (a + b) + (b + a)

log(36) = a + b + b + a

log(36) = 2a + 2b

5 0
2 years ago
Read 2 more answers
Which of the following is a step in evaluating: ∫ cos2 5x dx
Sav [38]
From the following choices, the correct step in evaluating: ∫ cos2 5x dx is 1 - cos 10x / 2dx.
4 0
3 years ago
HELP ASAP PLEASE!!!!
DENIUS [597]

Answer:

q=(1,5) t=(-2,3)r=(3,-1)s=(0,0)

Step-by-step explanation:

6 0
2 years ago
Which is the solution set of the inequality 15y-9 &lt; 36?
Kipish [7]

15y<36-9 ==>15y<27

y<27/15 ==>y<9/5

answer is B

6 0
2 years ago
Read 2 more answers
Honors Geometry QUiz- Please Help
viktelen [127]

Answer:

QUESTION 2:

The area of the polygon is 21.5 units²

QUESTION 3:

The area of the combined figure is 12 + 18.25·π units²

QUESTION 4:

The area of the figure is 40 units²

QUESTION 5

The area of the compost shape is 40 in.²

Step-by-step explanation:

QUESTION 2.

The area of the polygon is given as follows;

The area of two triangles + The area of trapezoid

1/2×6×3 + 1/2×3×4 + 1/2×(6 + 7) = 21.5 units²

QUESTION 3

The diameter of the semicircle, 'd', is given as follows;

d = √(8² + 3²) = √73

The area of the semicircle = π·d²/4 = π·73/4 = 18.25·π unit²

The area of the right triangle beside the semicircle is given as follows;

1/2 × 8 × 3 = 12 unit²

The area of the combined figure = The area of the semicircle + The area of the right triangle

∴ The area of the combined figure = 12 + 18.25·π units²

QUESTION 4:

The dimensions of the parallelogram are;

Width, W = √(4² + 1²) = √(17)

Length, L = √(8² + 2²) = √(68)

The area of the parallelogram, A_R = W × L = √(17) × √(68) = √(17 × 68) = 34

The area of the parallelogram, A_R = 34 units²

The length of a parallel side, 'A', of the parallelogram is A = 6

The height of the parallelogram, is h = 1

The area of the parallelogram is A = B·h = 6 × 1 = 6 units²

The area of the figure is the sum of the area of the rectangle and the area of the parallelogram

Therefore, we have;

The area of the figure = 34 units² + 6 units² = 40 units²

QUESTION 5

The composite shape consists of a triangle and a rectangle

Therefore, we have;

The area of the rectangle = 5 in. × 7 in. = 35 in.²

The area of the triangle = 1/2 × 2 in. × 5 in. = 5 in.²

The area of the compost shape = The area of the rectangle + The area of the triangle

∴ The area of the compost shape = 35 in.² + 5 in.² = 40 in.²

The area of the compost shape = 40 in.².

5 0
3 years ago
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