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masha68 [24]
3 years ago
10

A jewelry maker has 24 jade beads and 30 teak beads.What is the greatest number of necklaces she can make? How many beads of eac

h type are on each necklace?
Mathematics
2 answers:
gulaghasi [49]3 years ago
6 0

Jewelery maker has

24 jade beads

30 teak Beads

She has to make necklaces with each necklace having the same number of beads

So we need to find the highest common factor for both 24 and 30

The factors for both numbers are as follows

24 -1,2,3,4,6,8,12,24

30 - 1,2,3,5,6,10,15,30

The highest common factor for both is 6

The greatest number of necklaces she can make is 6

Number of jade beads - 24/6 = 4 jade beads

Number of teak beads - 30/6 = 5 teak beads

So each necklace will have 4 jade beads and 5 teak beads

Mkey [24]3 years ago
5 0
<span>A jewelry makes has 24 jade and 30 teak beads.
Find the number of necklace can a jewelry maker make with 24 jade beads and 30 teak beads
=> 8 x 3 = 24
=> 10 x 3 = 30
=> (8 + 10) x 3 = 24 + 30
=> 18 x 3 = 24 + 30
=> 54 + 54
Thus, a jewelry maker can make 3 necklace out of 54 beads.
There will be 8 jade beads in each necklace and 10 teak beads in each necklace

</span>



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