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qaws [65]
3 years ago
5

Determine the relation of AB and CD given the following points: A (3,-4), B (5.-7), C (8,3), and D (6,6).

Mathematics
1 answer:
MakcuM [25]3 years ago
8 0

Answer:

Step-by-step explanation:

To find the relationship between the given lines, we have to find the slope of both lines using slope formula, which is

So for AB, we will get

And for CD , we will get

Since the slopes of the two lines are equal , and when slopes are equal , lines are parallel .

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Fantom [35]

We will use tangent here as we are finding the opposite with the adjacent given.

So we can simply just put this into a calculator:

tan(68°) × 7 cm = AC

tan(68°) × 7 cm = 17.3 cm

3 0
2 years ago
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By what number should-15/56 be divided to get -5/6<br><br>pls pls pls pls I need your help ​
mr_godi [17]

Answer:

The desired divisor is n = 21

Step-by-step explanation:

Let that number be n.  Then:

-15/56        -5

---------- = ---------

     n            6

Through cross-multiplication we get:

(-15/56)*6 = -5n, which reduces to:

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2 years ago
$5000 at 6% for 9 months what is the balance
Kay [80]
I think it's suppose to go

6% is .06 divided by 12 which is .005 times the number of months so in this case 9 so 5,000 times .005 times 9 which is 225 so 5,000 plus an interest of 225 adds up to 5,225
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2 years ago
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Solving a trigonometric equation involving an angle multiplied by a constant
PIT_PIT [208]

In these questions, we need to follow the steps:

1 - solve for the trigonometric function

2 - Use the unit circle or a calculator to find which angles between 0 and 2π gives that results.

3 - Complete these angles with the complete round repetition, by adding

2k\pi,k\in\Z

4 - these solutions are equal to the part inside the trigonometric function, so equalize the part inside with the expression and solve for <em>x</em> to get the solutions.

1 - To solve, we just use algebraic operations:

\begin{gathered} \sqrt[]{3}\tan (3x)+1=0 \\ \sqrt[]{3}\tan (3x)=-1 \\ \tan (3x)=-\frac{1}{\sqrt[]{3}} \\ \tan (3x)=-\frac{\sqrt[]{3}}{3} \end{gathered}

2 - From the unit circle, we can see that we will have one solution from the 2nd quadrant and one from the 4th quadrant:

The value for the angle that give positive

+\frac{\sqrt[]{3}}{3}

is known to be 30°, which is the same as π/6, so by symmetry, we can see that the angles that have a tangent of

-\frac{\sqrt[]{3}}{3}

Are:

\begin{gathered} \theta_1=\pi-\frac{\pi}{6}=\frac{5\pi}{6} \\ \theta_2=2\pi-\frac{\pi}{6}=\frac{11\pi}{6} \end{gathered}

3 - to consider all the solutions, we need to consider the possibility of more turn around the unit circle, so:

\begin{gathered} \theta=\frac{5\pi}{6}+2k\pi,k\in\Z \\ or \\ \theta=\frac{11\pi}{6}+2k\pi,k\in\Z \end{gathered}

Since 5π/6 and 11π/6 are π radians apart, we can put them together into one expression:

\theta=\frac{5\pi}{6}+k\pi,k\in\Z

4 - Now, we need to solve for <em>x</em>, because these solutions are for all the interior of the tangent function, so:

\begin{gathered} 3x=\theta \\ 3x=\frac{5\pi}{6}+k\pi,k\in\Z \\ x=\frac{5\pi}{18}+\frac{k\pi}{3},k\in\Z \end{gathered}

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4 0
1 year ago
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svlad2 [7]

Answer:

x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z

Step-by-step explanation:

Solve for x:

2 sqrt(2) = 4^x

Hint: | Reverse the equality in 2 sqrt(2) = 4^x in order to isolate x to the left hand side.

2 sqrt(2) = 4^x is equivalent to 4^x = 2 sqrt(2):

4^x = 2 sqrt(2)

Hint: | Eliminate the exponential from the left hand side.

Take the logarithm base 4 of both sides:

Answer:x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z

8 0
3 years ago
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