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3 years ago

What is the Oder of 7/10 7/8 7/12 7/9

Mathematics

2 answers:

Verdich [7]3 years ago

6 0

Focus on the denominator, the bottom number. Put them in least to greatest.

Flauer [41]3 years ago

5 0

Least to Greatest Order -

7/12, 7/10, 7/9, 7/8
(Least) (Greatest)

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Which number is not in the solution set of x-6>10?

givi [52]

Answer:

options?

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The cost c, to produce b baseball bats per day is modeled by the function c(b)=0.06b^2 - 7.2b + 390. What number of bats should

Finger [1]

You have two choices.
The minimum possible cost to operate your bat factory for a day is $390,
and there are two quantities of bats that both cost that much.

One possibility:
   Produce no bats at all per day. Zero. Nada. None.
   Cost = 0.06(0)² - 7.2(0) + 390 = $390 per day.

The other choice:
   Produce 120 bats per day.
   Cost = 0.06(120²) - 7.2(120) + 390
      = 0.06(14,400) - 7.2(120) + 390
= 864 - 864 + 390
= $390 per day.

If you produce any other number of bats in a day ... more than zero
but not 120 ... then it will cost you more than $390 to operate the factory
that day.

8 0

3 years ago

Chevy has some yarn that he wants to use to make hats and scarves. Each hat uses 0.20.20, point, 2 kilograms of yarn and each sc

Rashid [163]

Answer:

The system of equation that represent this situations are;

$\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.$

Also 5 hats and 10 scarves can be prepared from 2 kg of yarn.

Step-by-step explanation:

Let number of hat Chevy makes be h.

Also Let number of scarves Chevy makes be s.

Given:

Total Amount of yarns = 2 kg

Total number of items = 15

Since Items need to make are hat and scarves.

Hence the equation can be represented as;

$h+s=15 \ \ \ \ equation \ 1$

Again Given:

Each hat uses 0.2 kilograms of yarn.

each scarf uses 0.1 kilograms of yarn.

Hence the equation can be represented as;

$0.2h+0.1s=2 \ \ \ \ \ equation \ 2$

Hence the system of equation that represent this situations are;

$\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.$

Now Solving these to find number of hats and number of scarves.

Multiplying equation 2 with 10 we get;

$10(0.2h+0.1s)=2\times 10\\10\times0.2h+10\times0.1s=20\\2h+s =20 \ \ \ \ \ equation \ 3$

Now Subtracting equation 1 from equation 3 we get;

$(2h+s)- (h+s) =20-15\\2h+s-h-s=5\\h= 5$

Now Substituting the value of h in equation 1 we get;

$h+s= 15\\5+s =15\\s=15-5\\s=10$

Hence 5 hats and 10 scarves can be prepared from 2 kg of yarn.

5 0

4 years ago

Nadia plans to paint her jewelry box. The box is shaped like a rectangular prism with the dimensions

Pachacha [2.7K]

Answer:

$132\ in^{2}$ is closest to the total surface area of the box

Step-by-step explanation:

we know that

The surface area of the box is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the box

we have

$L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in$

$W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in$

$H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in$

Find the area of the base B

$B=LW$

$B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}$

Find the perimeter of the base P

$P=2(L+W)$

$P=2(\frac{31}{4}+\frac{13}{4}))$

$P=2(\frac{44}{4})=22\ in$

Find the surface area

$SA=2(\frac{403}{16})+22(\frac{31}{8})$

$SA=(\frac{403}{8})+(\frac{682}{8})$

$SA=\frac{1,085}{8}=135.625\ in^{2}$

6 0

3 years ago

Find the circumference for 5 and 7

Thepotemich [5.8K]

Step-by-step explanation:

circumference = 2πr

5) 2πr

=2π(7)

= 43.98 mm

7) 2πr

=2π(29) -> 58÷2=29

=182.21 yd

4 0

3 years ago