1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Snowcat [4.5K]
3 years ago
13

How are vibrations different between bigger sizes rubber bands and smaller sized rubber bands?

Chemistry
1 answer:
arlik [135]3 years ago
5 0
Assuming the kind of vibration you are talking about is the kind where you stretch the rubber band between two points and then "twang" it, then the answer is fairly complex. What happens when you cause the vibrations to start is you make something called a "standing wave". In a standing wave, each particle in the rubber band has a certain amount of energy which causes it to move backwards and forwards, the particles with more energy have a larger "amplitude" (how much they move), and of course the particles with less energy have a smaller amplitude. Now a standing wave has two main components: The amplitude, and the frequency. The amplitude of the whole wave refers to the largest amplitude any particles has. The frequency refers to how often it takes for one of the particles to move between the two furthest away points it can be.
To compare rubber bands, you must remember to keep certain things constant. If you're looking at their vibrations, the amount of energy you use to "twang" the rubber band should be the same each time you twang it (which is the same as applying the same force each time you twang it).

A larger rubber band has more area over which to spread the energy, as well as it has more mass for the energy to move, so the vibrations will have smaller amplitudes, and smaller frequencies, overall vibrating less and with smaller vibrations. 
You might be interested in
The rate constant for the oxidation of nitric oxide by ozone is 2 x 10^14 molecule cm s, whereas that for the competing reaction
andreev551 [17]

Answer:

The NO + O3 is the dominant reaction.

Explanation:

First of all, let's convert to molecules/cm³;

For O3;

O3 at 40 ppb in atm= 4 x 10^(-8) atm and from ideal gas law PV = nRT or simplify n/V = P/RT

Thus, plugging in the relevant values to get;

n/V = [4 x 10^(-8)]/(0.0821 x 298) = 1.636 x 10^(-9)

So, n/V = 1.636 x 10^(-9) = (1.635 x 10-9 mol L-1)(6.02 x10^(23) molec/mol)(L/1000 cm3) =

9.84 x 10^(11) molecules/cm³

But from the question, NO has 2 moles, and thus concentration is;

2 x 9.84 x 10^(11) = 1.968 x 10^(12) molec/cm³

For O2;

Following the same pattern for O3, we obtain;

(0.21 atm)/[(0.0821 L atm mol-1 K-1)(298K)] = 5.167 x 1018 molecules/cm³

Now, for NO and O3 reaction the rate is; k[NO] [O3]

Thus rate;

= (2 x 10^(-14)cm³/molec.s)( 9.84 x 10^(11)molec/cm³)(1.968 x 10^(12) molec/cm³) = 3.9 molec/cm³.s

For 2NO + O2 → 2NO2 reaction, rate = k[NO]2 [O2]

Thus, rate;

= (2 x 10^(-38) cm^(6)/molec².s )( 1.968 x 10^(12) molec/cm³) ²

(5.167 x 1018 molec/cm³)

= 40,000 molec/cm³.s

Observing the two rates, it's clear that the NO + O3 is the dominant reaction.

6 0
2 years ago
At 25 °c, what is the hydroxide ion concentration, [oh–], in an aqueous solution with a hydrogen ion concentration of [h ] = 3.0
chubhunter [2.5K]

As,

Water has a pkw=14

so it can be represented as,

[H+] [OH-] = 1*10^-14

If [H+] = 3*10^-5M

[OH-] = (1*10^-14) / ( 3*10^-5)

[OH-] = 3.3*10^-9 M

5 0
3 years ago
A gas at 29.4 kPa is cooled from a temperature of 75°C to a temperature of 25°C at constant volume. What is the new pressure of
kirill115 [55]

<span>To solve this we assume that the gas inside the balloon is an ideal </span>gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant volume pressure and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

 

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 25 x 29.4 / 75

P2 = 9.8 kPa

7 0
3 years ago
Read 2 more answers
Is sugar a compound or a mixture?
puteri [66]

Answer:

compound

Explanation:

3 0
2 years ago
Read 2 more answers
Is dew forming on a leaf a physical or chemical change?
solong [7]
No, the formation of dew is condensation, which is a physical change.
5 0
3 years ago
Other questions:
  • Th e molar absorption coeffi cients of tryptophan and tyrosine at 240 nm are 2.00 × 103 dm3 mol−1 cm−1 and 1.12 × 104 dm3 mol−1
    14·1 answer
  • What mass of propane (C3H8) is needed to produce 346 g carbon dioxide in the following reaction? A. 346 g C3H8 B. 1.86 g C3H8 C.
    10·2 answers
  • Identify the element that has 6 valence electrons and 3 energy levels
    14·1 answer
  • In a car cylinder, a piston moves up and down inside a cylinder, causing the substance inside to expand and contract. Which type
    5·1 answer
  • Which actions is due to field forces <br>​
    9·1 answer
  • What mass of propane is necessary to react with the amount of oxygen in the chemical formula C3H8 + 5O2 → 3CO2 + 4H2O
    5·1 answer
  • Which of the following materials has the highest density?
    13·1 answer
  • For the reaction between ammonium phosphate and lead (IV) nitrate, producing ammonium nitrate and lead (IV) phosphate, how many
    14·1 answer
  • Jack is melting butter in a pan. He observes a clear liquid with many solid particles floating in it. Based on Jack's observatio
    7·1 answer
  • Which describes a molecule? (Select all that apply.)
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!