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natulia [17]
2 years ago
8

What type of energy does a person experience when jumping on a trampoline?

Chemistry
1 answer:
Fofino [41]2 years ago
7 0

Answer:

Knetic

Explanation:

When you jump on a trampoline, your body has kinetic energy that changes over time. As you jump up and down, your kinetic energy increases and decreases with your velocity. Your kinetic energy is greatest, just before you hit the trampoline on the way down and when you leave the trampoline surface on the way up.

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One atom of silicon can properly be combined in a compound with
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your answer is c. two atoms of oxygen.

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3 years ago
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blondinia [14]

2, 4, 1

Explanation:

We have the following chemical reaction:

Ag₂O → Ag + O₂

To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

So the balanced chemical equation is:

2 Ag₂O → 4 Ag + O₂

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balancing chemical equations

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3 years ago
What does the number 7 mean in the following example-73Li?
Pavlova-9 [17]

Answer:

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a 3

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3 years ago
How old was the oldest animal fossil <br>help thx​
JulijaS [17]

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5 0
3 years ago
The pH of 0.10 M solution of an acid is 6. What is the acid dissociation constant of the acid?
svlad2 [7]

Answer: Dissociation constant of the acid is 10^{-11}.

Explanation: Assuming the acid to be monoprotic, the reaction follows:

                         HA\rightleftharpoons H^++A^-

pH of the solution = 6

and we know that

pH=-log([H^+])

[H^+]=antilog(-pH)

[H^+]=antilog(-6)=10^{-6}M

As HA ionizes into its ions in 1 : 1 ratio, hence

[H^+]=[A^-]=10^{-6}M

As the reaction proceeds, the concentration of acid decreases as it ionizes into its ions, hence the decreases concentration of acid at equilibrium will be:

[HA]=[HA]-[H^+]

[HA]=0.1M-10^{-6}M

[HA]=0.09999M

Dissociation Constant of acid, K_a is given as:

K_a=\frac{[A^-][H^+]}{HA}

Putting values of [H^+],[A^-]\text{ and }[HA] in the above equation, we get

K_a=\frac{(10^{-6}M).(10^{-6}M)}{0.09999M}

K_a=1.0001\times 10^{-11}M

Rounding it of to one significant figure, we get

K_a=1.0\times 10^{-11}M\approx 10^{-11}M

6 0
3 years ago
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