Answer:
- stress equation :
- Shear stress equation :
- cross sectional area of a beam equation : b*d
- cross sectional area of a shaft equation :
- shear stress at an angle to the axis of the member equation:
sin∅cos∅. - Normal stress at an angle to the axis of the member equation:
∅ - factor of safety equation :
- strain under axial loading equation:
Explanation:
The description of all the pieces to the equations
- stress equation : p = axial force, A = cross sectional area
- Shear stress equation : Q = calculated statistical moment, I = moment of inertia, v = calculated shear, b = width of beam
- cross sectional area of a beam equation : b*d b=width of beam, d =depth of beam
- cross sectional area of a shaft equation : d = shaft diameter
- shear stress at an angle to the axis of the member equation: sin∅cos∅. P = axial force, A = cross sectional area ∅ = given angle
- Normal stress at an angle to the axis of the member equation: ∅ p = axial force , A = cross sectional area, ∅ = given angle
- factor of safety equation :
- strain under axial loading equation: P = axial force, L = length, A = cross sectional area, E = young's modulus
Answer and Explanation:
TEMPERATURE DEPENDENCY ON ELECTRICAL CONDUCTIVITY OF METALS : Metals are good conductors of electricity but when we increase the temperature the free electrons of metals collide with each other due to heat.There collision become very fast and so the resistance increases and so the electrical conductivity of metals decreases on increasing temperature.
TEMPERATURE DEPENDENCY ON ELECTRICAL CONDUCTIVITY OF SEMICONDUCTOR : The electrical conductivity of semiconductor is mainly sue to presence of impurities and defects as the temperature increases the impurities and defects also increases so the electrical conductivity of semiconductor increases on increasing temperature.
Answer:
A) m' = 351.49 kg/s
B) m'= 1036.91 kg/s
Explanation:
We are given;
Pressure Ratio;r_p = 12
Inlet temperature of compressor;T1 = 300 K
Inlet temperature of turbine;T3 = 1000 K
cp = 1.005 kJ/kg·K
k = 1.4
Net power output; W' = 70 MW = 70000 KW
A) Now, the formula for the mass flow rate using the total power output of the compressor and turbine is given as;
m' = W'/[cp(T3(1 - r_p^(-(k - 1)/k)) - T1(r_p^((k - 1)/k))
At, 100% efficiency, plugging in the relevant values, we have;
m' = 70000/(1.005(1000(1 - 12^(-(1.4 - 1)/1.4)) - 300(12^((1.4 - 1)/1.4)))
m' = 70000/199.1508
m' = 351.49 kg/s
B) At 85% efficiency, the formula will now be;
m' = W'/[cp(ηT3(1 - r_p^(-(k - 1)/k)) - (T1/η) (r_p^((k - 1)/k))
Where η is efficiency = 0.85
Thus;
m' = 70000/(1.005(0.85*1000(1 - 12^(-(1.4 - 1)/1.4)) - (300/0.85)(12^((1.4 - 1)/1.4)))
m' = 70000/(1.005*(432.09129 - 364.9189)
m'= 1036.91 kg/s
Answer:
Explanation:
Usar motores eléctricos en aviones ofrece numerosas ventajas reales. A diferencia de los motores de combustión interna los motores eléctricos no necesitan aire para funcionar, lo que significa que pueden mantener toda su capacidad y potencia incluso a altitudes elevadas donde el aire es más tenue.
