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morpeh [17]
3 years ago
14

Kjhwe ,kenwif ujwfeowlwfwfwfw...

Engineering
2 answers:
Rashid [163]3 years ago
5 0
I’m so confused but ok
quester [9]3 years ago
4 0

Answer:

Unclear.

Explanation:

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Engine oil flows through a 25‐mm‐diameter tube at a rate of 0.5 kg/s. The oil enters the tube at a temperature of 25°C, while th
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Answer:

a) the log mean temperature difference (Approx. 64.5 deg C)

b) the rate of heat addition into the oil.

The above have been solved for in the below workings

Explanation:

3 0
4 years ago
What is the focus of 7th grade civics
Jobisdone [24]
C. seems like the best answer. i may be wrong so don’t quote me on that
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how many people were asked though

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8 0
3 years ago
Which stroke in the four stroke cycle begins as the piston reaches BDC after combustion takes place
Svet_ta [14]

Explanation:

Which stroke in the four stroke cycle begins as the piston reaches BDC after combustion takes place?

Answer :Exhaust stroke is the waste gasses discharging process into the atmosphere after the combustion stroke. This step takes place after the piston reaches the BDC at the end of the combustion stroke. When the piston reaches BDC, the piston will definitely move back to TDC.

This is the Answer for your question :3

I hoped I helped you :3

I hope you are having a great day ❤️❤️❤️

8 0
3 years ago
Given an N x M matrix and a dictionary containing K distinct words of length between 1 and 30 symbols, the Word Search should re
Ket [755]

Answer:

import java.util.*;

public class Main {

  public static String[] wordSearch(char[][] matrix, String[] words) {

      int N = matrix.length;

      List<String> myList = new ArrayList<String>();

      int pos = 0;

      for(String word : words)

      {

      for (int i = 0; i < N; i++) {

          for (int j = 0; j < N; j++) {

              if (search(matrix, word, i, j, 0, N)) {

              if(!myList.contains(word))

              {

              myList.add(word);

              }

              }

          }

      }

      }

     

      String[] newDict = myList.toArray(new String[myList.size()]);

     

  return newDict;

  }

  public static boolean search(char[][] matrix, String word, int row, int col,

          int index, int N) {

      // check if current cell not already used or character in it is not not

      if (word.charAt(index) != matrix[row][col]) {

          return false;

      }

      if (index == word.length() - 1) {

          // word is found, return true

          return true;

      }

             

      // check if cell is already used

      if (row + 1 < N && search(matrix, word, row + 1, col, index + 1, N)) { // go

                                                                              // down

          return true;

      }

      if (row - 1 >= 0 && search(matrix, word, row - 1, col, index + 1, N)) { // go

                                                                              // up

          return true;

      }

      if (col + 1 < N && search(matrix, word, row, col + 1, index + 1, N)) { // go

                                                                              // right

          return true;

      }

      if (col - 1 >= 0 && search(matrix, word, row, col - 1, index + 1, N)) { // go

                                                                              // left

          return true;

      }

      if (row - 1 >= 0 && col + 1 < N

              && search(matrix, word, row - 1, col + 1, index + 1, N)) {

          // go diagonally up right

          return true;

      }

      if (row - 1 >= 0 && col - 1 >= 0

              && search(matrix, word, row - 1, col - 1, index + 1, N)) {

          // go diagonally up left

          return true;

      }

      if (row + 1 < N && col - 1 >= 0

              && search(matrix, word, row + 1, col - 1, index + 1, N)) {

          // go diagonally down left

          return true;

      }

      if (row + 1 < N && col + 1 < N

              && search(matrix, word, row + 1, col + 1, index + 1, N)) {

          // go diagonally down right

          return true;

      }

      // if none of the option works out, BACKTRACK and return false

         

      return false;

  }

  public static void main(String[] args) {

      char[][] matrix = { { 'j', 'a', 's' },

              { 'a', 'v', 'o'},

              { 'h', 'a', 'n'} };

 

  String[] arr_str = {"a", "java", "vaxn", "havos", "xsds", "man"};

 

     

      arr_str = wordSearch(matrix, arr_str);

     

      for(String str : arr_str)

      {

      System.out.println(str);

      }

  }

}

8 0
4 years ago
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