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Usimov [2.4K]
3 years ago
15

. A roadway is being designed capable of allowing 70 mph vehicle speed. The superelevation around one curve is 0.05 inches per i

nch and the coefficient of side friction is 0.09. (a) Determine the minimum radius of the curve to the vehicle to provide safe travel. (b) Suppose the radius of the curve to the center of the vehicle is only 1500 feet. What speed limit will need to be posted for safe travel through the curve
Engineering
1 answer:
adelina 88 [10]3 years ago
6 0

The minimum radius of the curve to the vehicle to provide safe travel is 2339.2 ft

<u>Explanation:</u>

Given -

Speed allowed, v = 70mph

1 mph = 1.467 fps (feet per second)

Therefore, v = 70 X 1.467 fps

Superelevation, e = 0.05 inches/inch

Coefficient of side friction, fs = 0.09

Minimum radius of the curve, r = ?

We know,

r = v² / g ( fs + e/100 )

where,

g = acceleration due to gravity in feet

g = 32.2 lb.ft / lbf.s²

r = ( 70 X 1.467 )² / 32.2 ( 0.09 + 0.05 )

r = 2339.2 ft

Therefore, the minimum radius of the curve to the vehicle to provide safe travel is 2339.2 ft

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A cylinder fitted with a frictionless piston contains 2 kg of R-134a at 3.5 bar and 100 C. The cylinder is now cooled so that th
inna [77]

Answer:

The answer to the question is

The heat transferred in the process is -274.645 kJ

Explanation:

To solve the question, we list out the variables thus

R-134a = Tetrafluoroethane

Intitial Temperaturte t₁ = 100 °C

Initial pressure = 3.5 bar = 350 kPa

For closed system we have m₁ = m₂ = m

ΔU = m×(u₂ - u₁) = ₁Q₂ -₁W₂

For constant pressure process we have

Work done = W = \int\limits^a_b P \, dV  = P×ΔV = P × (V₂ - V₁) = P×m×(v₂ - v₁)

From the tables we have

State 1 we have h₁ = (490.48 +489.52)/2 = 490 kJ/kg

State 2 gives h₂ = 206.75 + 0.75 × 194.57= 352.6775 kJ/kg

Therefore Q₁₂ = m×(u₂ - u₁) + W₁₂ = m × (u₂ - u₁) + P×m×(v₂ - v₁)

= m×(h₂ - h₁) = 2.0 kg × (352.6775 kJ/kg - 490 kJ/kg) =-274.645 kJ

5 0
2 years ago
declare integer product declare integer number product = 0 do while product &lt; 100 display ""Type your number"" input number p
Brilliant_brown [7]

Full Question

1. Correct the following code and

2. Convert the do while loop the following code to a while loop

declare integer product

declare integer number

product = 0

do while product < 100

display ""Type your number""

input number

product = number * 10

loop

display product

End While

Answer:

1. Code Correction

The errors in the code segment are:

a. The use of do while on line 4

You either use do or while product < 100

b. The use of double "" as open and end quotes for the string literal on line 5

c. The use of "loop" statement on line 7

The correction of the code segment is as follows:

declare integer product

declare integer number

product = 0

while product < 100

display "Type your number"

input number

product = number * 10

display product

End While

2. The same code segment using a do-while statement

declare integer product

declare integer number

product = 0

Do

display "Type your number"

input number

product = number * 10

display product

while product < 100

4 0
3 years ago
What do you own that might not be manufactured?
horrorfan [7]

Answer:

A pet

Explanation:

Latin time I checked animals aren't made by people? I honestly don't know if this helps but I'm technically not wrong.

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3 years ago
Training is a way for employers to provide ____ to enable employees to protect themselves and others from injuries.
Andreyy89

Answer:

Training is a way for employers to provide tools to enable employees to protect themselves and others from injuries.

Explanation:

5 0
2 years ago
Read 2 more answers
Block A hangs by a cord from spring balance D and is submerged in a liquid C contained in beaker B. The mass of the beaker is 1.
nikitadnepr [17]

Answer:

a)  m_e= 3.05 Kg

b)  \rho=1072.3kg/m^3

c)  m_e= 3.05 Kg

Explanation:

From the question we are told that:

Beaker Mass m_b=1.20

Liquid Mass m_l=1.85

Balance D:

Mass m_d=3.10

Balance E:

Mass m_e=7.50

Volume v=4.15*10^{-3}m^3

a)

Generally the equation for Liquid's density is mathematically given by

m_e=m_b+m_l+(\rho*v)

\rho=\frac{7.50-(1.2+1.85)}{4.15*10^{-3}}

\rho=1072.3kg/m^3

b)

Generally the equation for D's Reading at A pulled is mathematically given by

m_d = mass of block - mass of liquid displaced

m_d=m- (\rho *v )

m=3.10+ (1072.30 *4.15*10^{-3}m^3 )

m=18.10kg

c)

Generally the equation for E's Reading at A pulled is mathematically given by

m_e=m_b+m_l

m_e = 1.20 + 1.85

m_e= 3.05 Kg

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